Question

我想将列表扩展或附加到另一个列表的内容：我有以下内容：

l = (('AA', 1.11,'DD',1.2), ('BB', 2.22, 'EE', 2.3), ('CC', 3.33, 'FF', 3.45))
ls = [('XX', 7.77), ('YY', 8.88), ('ZZ', 9.99)]
m = ['first', 'second', 'third']
for i in range(len(l)):
    result = []
    for n in m:
        if n == "first":
            r=[]
            for word, number in ls[i]:
                temp = [word, number]
                r.append(temp)
            for t in r:
                result.extend(t)
            print result

我希望在上面的代码中打印出'result'时会看到以下结果（每个都在换行符中）：

['AA', 1.11, 'XX', 7.77]
['BB', 2.22, 'YY', 8.88]
['CC', 3.33, 'ZZ', 9.99]

非常感谢提前。

Answer 1

您所需要的只是zip：

l = (('AA', 1.11), ('BB', 2.22), ('CC', 3.33))
ls = [('XX', 7.77), ('YY', 8.88), ('ZZ', 9.99)]

for x,y in zip(l,ls):
    print(list(x+y))

# ['AA', 1.1100000000000001, 'XX', 7.7699999999999996]
# ['BB', 2.2200000000000002, 'YY', 8.8800000000000008]
# ['CC', 3.3300000000000001, 'ZZ', 9.9900000000000002]

Answer 2

您需要zip功能：

>>> for x in zip(l, ls):
>>>     list1, list2 = x
>>>     print list1 + list2

>>> ['AA', 1.1100000000000001, 'XX', 7.7699999999999996]
>>> ['BB', 2.2200000000000002, 'YY', 8.8800000000000008]
>>> ['CC', 3.3300000000000001, 'ZZ', 9.9900000000000002]

1：http://docs.python.org/library/functions.html#zip“zip

Answer 3

这是一种方式：

import itertools

for a, b, c in itertools.izip(l, ls, m):
    result = list(a) + list(b) +  [c]
    print result

输出：

['AA', 1.1100000000000001, 'XX', 7.7699999999999996, 'first']
['BB', 2.2200000000000002, 'YY', 8.8800000000000008, 'second']
['CC', 3.3300000000000001, 'ZZ', 9.9900000000000002, 'third']

扩展/追加清单

3 个答案: