我在使用JSON解析时遇到了一些问题。当我点击URL时,我得到了像这样的JSON响应:
//JSON 1
{ "data":
{"array":
["3",
{"array":
[
{"id":"1","message":"Hello","sender":"inot"},
{"id":"2","message":"World","sender":"inot"},
{"id":"3","message":"Hi","sender":"marza"}
]
}
]
},
"message":"MSG0001:Success",
"status":"OK"
}
但是如果数据的结果只是1,则JSON响应是这样的:
//JSON 2
{ "data":
{"array":
["3",
{"array":
{"id":"3","message":"Hi","sender":"marza"}
}
]
},
"message":"MSG0001:Success",
"status":"OK"
}
我实现此代码以获取id,message和sender值,并在JSON 1上正常工作,但在JSON 2上出错。我使用JSON-Framework。问题是如何检测JSON响应是对象({})还是数组([])??
// Parse the string into JSON
NSDictionary *json = [myString JSONValue];
// Get all object
NSArray *items = [json valueForKeyPath:@"data.array"];
NSArray *array1 = [[items objectAtIndex:1] objectForKey:@"array"];
NSEnumerator *enumerator = [array1 objectEnumerator];
NSDictionary* item;
while (item = (NSDictionary*)[enumerator nextObject]) {
NSLog(@"id = %@",[item objectForKey:@"id"]);
NSLog(@"message = %@",[item objectForKey:@"message"]);
NSLog(@"sender = %@",[item objectForKey:@"sender"]);
}
答案 0 :(得分:15)
您可以使用id
并检查您获得的对象是NSArray还是NSDictionary:
id item = [json valueForKeyPath:@"data.array"];
if ([item isKindOfClass:[NSArray class]]) {
// item is an array
}
else if ([item isKindOfClass:[NSDictionary class]]) {
// item is a dictionary
}