Question

我需要帮助。我必须从excel创建测试用例，格式如下：

**Current   NextState    Function Type**

GREETING-1,repeat,PMSG

REPEAT,CallerType,PMSG

CALLERTYPE,XferBridges(DTMF:1),ClaimMenu(DTMF:2),XferLine2(DTMF:3),XferLine2(DTMF:4),Menu

CLAIMMENU,RejectMenu(DTMF:1),XferLine2(DTMF:2),Menu

REJECTMENU,NotCovered(DTMF:1),Terminated(DTMF:2),NMCard(DTMF:3),NMGroup(DTMF:4),Refill(DTMF:5),NoDrugNDC(DTMF:6),XferLine2(DTMF:2),Menu

NOTCOVERED,RejectMenu(DTMF:1),Menu

TERMINATED,XferLine2(DTMF:1),Menu

NMCARD,XferLine2(DTMF:1),Menu

NMGROUP,XferLine2(DTMF:1),Menu

REFILL,XferLine2(DTMF:1),Menu

NODRUGNDC,XferLine2(DTMF:1),Menu

XFERBRIDGES,STOP,PMSG

XFERLINE2,STOP,PMSG

THANKYOU,GoodBye,PMSG

GOODBYE,STOP,PMSG

该工具将生成n个测试用例。请指导我将编写哪些代码可以生成以下类型的测试用例：

Case 1: Greeting-1 -> Repeat -> CallerType, Press DTMF 1 ->XferBridges ->STOP

Case 2: Greeting-1 -> Repeat -> CallerType, Press DTMF 2 ->ClaimMenu, Press DTMF 1 -> RejectMenu, Press DTMF 1 ->NotCovered, Press DTMF1 -> RejectMenu -> STOP( from entering infinte into loop)

Case 3: Greeting-1 -> Repeat -> CallerType, Press DTMF 2 ->ClaimMenu, Press DTMF 1 -> RejectMenu, Press DTMF 2 -> Terminated, Press DTMF 1 ->XferLine2 ->STOP

Case 4: Greeting-1 -> Repeat -> CallerType, Press DTMF 2 ->ClaimMenu, Press DTMF 1 -> RejectMenu, Press DTMF 3 -> NMCard, Press DTMF 1 ->XferLine2 ->STOP

**.**


**.**

等等

你可能已经知道我在这里做了什么。尝试为每个调用流创建测试用例，如果下一个状态是PMSG然后将其添加到同一个数组，但是如果下一个状态是MENU则创建新数组（这意味着新的测试用例）将通过所有DTMF选项及其相应的下一个状态等等

我使用递归循环来获取输出，但是它给出了错误的值。

代码：

function generateTestCaseList(nextState) {
		var incCount = 1;
		
		var positionInt = findNextState(nextState);
		var tempStoredArray = allState[positionInt];
		
		if(tempStoredArray[0].toLowerCase() == menuName.toLowerCase())
		{
			incCount = menuPostion;
			f = true;
		}	
		else if(tempStoredArray[0].toLowerCase() == nextMenuName.toLowerCase())
			incCount = nextMenuPostion;
					
		var tempStr = getState(tempStoredArray, incCount);
		var tempArr = tempStr.toLowerCase().split("%");
		
		nextState = tempArr[1];
		parentStr = parentStr + tempArr[0];
		var cntInfi = parentStr.toLowerCase().split(nextState).length -1;
		
		if(cntInfi == 2)
		{
			return parentStr;
		}
		else if(nextState != "stop")
		{
			var pstInt = findNextState(nextState);
			var tempArr = allState[pstInt];
			
			if(tempArr[tempArr.length -1] == "Menu" && f == true)
			{	
				nextMenuName = tempArr[0];
				var tempMenuPsx= tempArr.length - 2;
				//WScript.Echo("tempMenuPsx"+nextMenuName+tempMenuPsx);
				for(var k=tempMenuPsx;k >0 ;k--)
				{
					nextMenuPostion = k;
					//WScript.Echo("nextMenuPostion"+nextMenuPostion);
					WScript.Echo("parentStr"+parentStr);
					var temp = generateTestCaseList(nextState);
					childStr = childStr +temp;
					resultList.push(childStr);
					childStr = "";
					
				}
				
			}
			else
			{
				 generateTestCaseList(nextState);
			}
			
		}
		else
		{
			return parentStr;
		}
		
}

function findNextState(nextState) {
	
	for(var l=0;l<allState.length;l++)
	{
		if(allState[l][0].toLowerCase()==nextState.toLowerCase())
			return l;
	}
	return 0;			
}

function getState(tempArray,l) {
	
	var tempStr = tempArray[0];
				
	if(tempArray[2] =="GETV")
		tempStr = tempStr +";Voice: Say Something;"+tempArray[2]+";$%"+tempArray[1];
	else if(tempArray[2] =="PMSG")
		tempStr = tempStr +";"+tempArray[2]+";$%"+tempArray[1];
	else
		tempStr = tempStr +";DTMF:"+l+";"+tempArray[tempArray.length -1]+";$%"+tempArray[l];
		
	return tempStr;
}

结果（“$”是此处的下一个状态分隔符）：

1. greeting-1;pmsg;$repeat;pmsg;$callertype;dtmf:4;menu;$xferline2;pmsg;$
2. greeting-1;pmsg;$repeat;pmsg;$callertype;dtmf:3;menu;$xferline2;pmsg;$
3. greeting-1;pmsg;$repeat;pmsg;$callertype;dtmf:2;menu;$claimmenu;dtmf:2;menu;$xferline2;pmsg;$claimmenu;dtmf:1;menu;$rejectmenu;dtmf:7;menu;$xferline2;pmsg;$rejectmenu;dtmf:6;menu;$nodrugndc;dtmf:1;menu;$

4. greeting-1;pmsg;$repeat;pmsg;$callertype;dtmf:2;menu;$claimmenu;dtmf:2;menu;$xferline2;pmsg;$claimmenu;dtmf:1;menu;$rejectmenu;dtmf:7;menu;$xferline2;pmsg;$rejectmenu;dtmf:6;menu;$nodrugndc;dtmf:1;menu;$rejectmenu;dtmf:1;menu;$notcovered;dtmf:1;menu;$rejectmenu;dtmf:7;menu;$

5. greeting-1;pmsg;$repeat;pmsg;$callertype;dtmf:2;menu;$claimmenu;dtmf:2;menu;$xferline2;pmsg;$claimmenu;dtmf:1;menu;$rejectmenu;dtmf:7;menu;$xferline2;pmsg;$rejectmenu;dtmf:6;menu;$nodrugndc;dtmf:1;menu;$rejectmenu;dtmf:1;menu;$notcovered;dtmf:1;menu;$rejectmenu;dtmf:7;menu;$rejectmenu;dtmf:6;menu;$nodrugndc;dtmf:1;menu;$

输出包含单个呼叫流程中的所有DTMF选项。任何输入都会有很大的帮助。

Answer 1

我已经得到了解决方案，它效率不高但确实提供了所需的输出。

＆＃13;

function generateTestPlan() {
	
	var menuCount = 0;
	for(var g=0;g<allState.length;g++)
	{
		var tempArr = allState[g];
		
		if(tempArr[tempArr.length-1] == "Menu")
		{
			var tempArr = [];
			tempArr.push(allState[g][0]);
			for(var i =1;i<allState[g].length-1; i++)
			{
				tempArr.push(allState[g][i]);
				menuCount++;
			}
			
			menuList.push(tempArr);
		}
	}
	var firstState = allState[0][0];
		
	for(var k=0;k < menuCount*1000;k++)
	{
		getCallFlow(firstState,stack1)
		stack.push(stack1);
		stack1 = [];
	}
	
	stack = eliminateDuplicates(stack);

}

function getCallFlow (nextState,stack1)
{
		var positionInt = findNextState(nextState);
		var tempStoredArray = allState[positionInt];
		
		var g = 0;
		for(var b= 0; b < menuList.length ;b++)
		{
			if(menuList[b][0] == tempStoredArray[0])
			{
				var len = menuList[b].length -1;
				g =Math.floor(Math.random() * len) + 1 ; 
			}
		}
		
		var tempStr = getState(tempStoredArray,g);
		
		var tempArr = tempStr.toLowerCase().split("%");
		var nextState1 = "";
		var multipleGoto = tempArr[1].toLowerCase().split("@").length -1;
		
		if(multipleGoto > 1)
		{
			var multipleArray = tempArr[1].toLowerCase().split("@");
			//WScript.Echo(multipleArray)
			var len = multipleArray.length -1;
			var choose =Math.floor(Math.random() * len) + 1  ;
			//WScript.Echo(choose)
			nextState1 = multipleArray[choose];
			//WScript.Echo(nextState1)
		}
		else
		{
			nextState1 = tempArr[1];
		}
		
		stack1.push(tempArr[0]);
		
		if(checkIfArrayIsUnique(stack1) == false)
		{
			stack1.push("stop");
			return ;
		}
		
		if(nextState1 == "stop")
		{
			stack1.push("stop");
			return ;
		}
		else
		{
			getCallFlow(nextState1,stack1);
		}
		
}
function findNextState(nextState) {
	
	for(var l=0;l<allState.length;l++)
	{
		if(allState[l][0].toLowerCase()==nextState.toLowerCase())
			return l;
	}
	return 0;			
}

＆＃13;

Java Script：如何根据给定的输入创建测试用例

1 个答案: