来自绘图对象的matplotlib子图

时间:2015-09-24 14:30:05

标签: python matplotlib plot

我有一系列函数返回三个绘图对象(图形,轴和图),我想将它们组合成一个单独的图形作为子图。我已将示例代码放在一起:

import matplotlib.pyplot as plt
import numpy as np

def main():

    line_fig,line_axes,line_plot=line_grapher()
    cont_fig,cont_axes,cont_plot=cont_grapher()

    compound_fig=plot_compounder(line_fig,cont_fig)#which arguments?

    plt.show()

def line_grapher():
    x=np.linspace(0,2*np.pi)
    y=np.sin(x)/(x+1)

    line_fig=plt.figure()
    line_axes=line_fig.add_axes([0.1,0.1,0.8,0.8])
    line_plot=line_axes.plot(x,y)
    return line_fig,line_axes,line_plot

def cont_grapher():
    z=np.random.rand(10,10)

    cont_fig=plt.figure()
    cont_axes=cont_fig.add_axes([0.1,0.1,0.8,0.8])
    cont_plot=cont_axes.contourf(z)
    return cont_fig,cont_axes,cont_plot

def plot_compounder(fig1,fig2):
    #... lines that will compound the two figures that
    #... were passed to the function and return a single
    #... figure
    fig3=None#provisional, so that the code runs
    return fig3

if __name__=='__main__':
    main()

将一组图表合并为一个函数非常有用。有没有人这样做过?

1 个答案:

答案 0 :(得分:1)

如果你打算在同一个数字上绘制图表,那么就不需要为每个情节创建一个数字。将绘图函数更改为仅返回轴,可以实例化带有两个子图的图形,并为每个子图添加一个轴:

def line_grapher(ax):
    x=np.linspace(0,2*np.pi)
    y=np.sin(x)/(x+1)

    ax.plot(x,y)


def cont_grapher(ax):
    z=np.random.rand(10,10)

    cont_plot = ax.contourf(z)

def main():

    fig3, axarr = plt.subplots(2)
    line_grapher(axarr[0])
    cont_grapher(axarr[1])

    plt.show()


if __name__=='__main__':
    main()

查看plt.subplots函数和add_subplot数字方法,在一个数字上绘制多个图。