我想在用户选中屏幕时立即释放快门。我有工作代码以全屏模式显示相机。如何通过触摸触发快门?
- (IBAction) takePicture { if (!self.imgPicker) { self.imgPicker = [[UIImagePickerController alloc] init]; self.imgPicker.allowsEditing = NO; self.imgPicker.delegate = self; } if ([UIImagePickerController isSourceTypeAvailable:UIImagePickerControllerSourceTypeCamera]) { self.imgPicker.sourceType = UIImagePickerControllerSourceTypeCamera; self.imgPicker.showsCameraControls = NO; self.imgPicker.wantsFullScreenLayout = YES; CGAffineTransform cameraTransform = CGAffineTransformMakeScale(1.132, 1.132); self.imgPicker.cameraViewTransform = cameraTransform; UIView *headsUpView = [[UIView alloc] initWithFrame:CGRectMake(0, 0, 480, 320)]; [self.imgPicker setCameraOverlayView:headsUpView]; } else { NSLog(@"Camera not available."); self.imgPicker.sourceType = UIImagePickerControllerSourceTypeSavedPhotosAlbum; } [self presentModalViewController:self.imgPicker animated:YES]; }
答案 0 :(得分:2)
您应该使用takePicutre方法,然后检测屏幕上的任何触摸。
像这样的东西
-(void) touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
UITouch *touch = [[event allTouches] anyObject];
self.imgPicker.takePicture;
}