Question

我查看了堆栈上的相关问题。我试图将我的查询排序为按升序显示月份。 Stack上的一篇类似帖子说我必须指出＆＃34; ASC＆＃34;，但这对我不起作用。我写了一个Order By。我无法弄清楚它为什么不起作用。

SELECT  DATENAME( MONTH,(Submission.SubmissionDate)) AS [Date]        
FROM Submission 
GROUP BY DATENAME( MONTH,(Submission.SubmissionDate)) ORDER BY [Date] ASC;

这是输出：

  Month
  August
 February
 September

注意：这只是我查询的一部分，我不认为有必要显示其余内容，这与我的表中的其他属性相关（不是月份相关）

编辑：这是我的整个查询:(初始一个）

SELECT  DATENAME( MONTH,(Submission.SubmissionDate)) AS [Date], 
SUM( CASE WHEN Submission.Status='Under review' THEN 1 ELSE 0 END) [Under_Review], 
SUM( CASE WHEN Submission.Status='Accepted' THEN 1 ELSE 0 END) [Accepted], 
SUM( CASE WHEN Submission.Status='Rejected' THEN 1 ELSE 0 END) [Rejected], 
SUM( CASE WHEN Submission.Status='In print' THEN 1 ELSE 0 END) [In_print], 
SUM( CASE WHEN Submission.Status='Published' THEN 1 ELSE 0 END) [Published] 
FROM Submission INNER JOIN ((Faculty INNER JOIN School ON Faculty.FacultyID = School.[FacultyID]) INNER JOIN (Researcher INNER JOIN ResearcherSubmission ON Researcher.ResearcherID = ResearcherSubmission.ResearcherID) ON School.SchoolID = Researcher.SchoolID) ON Submission.SubmissionID = ResearcherSubmission.SubmissionID 
GROUP BY DATENAME( MONTH,(Submission.SubmissionDate)) 
ORDER BY DATENAME( MONTH,(Submission.SubmissionDate));

Answer 1

SELECT  DATENAME( MONTH, Submission.SubmissionDate) AS [Date]        
FROM Submission 
ORDER BY datepart(mm,Submission.SubmissionDate)

您不需要group by（对于显示的查询）。此外，当您order by month name时，它会按字母顺序month name返回结果。您不应在alias，where order by和having条款中使用先前定义的group by es。

编辑：问题在于join条件。你应该按照行中的评论来纠正它们。

SELECT DATENAME( MONTH,(Submission.SubmissionDate)) AS [Date], 
SUM( CASE WHEN Submission.Status='Under review' THEN 1 ELSE 0 END) [Under_Review], 
SUM( CASE WHEN Submission.Status='Accepted' THEN 1 ELSE 0 END) [Accepted], 
SUM( CASE WHEN Submission.Status='Rejected' THEN 1 ELSE 0 END) [Rejected], 
SUM( CASE WHEN Submission.Status='In print' THEN 1 ELSE 0 END) [In_print], 
SUM( CASE WHEN Submission.Status='Published' THEN 1 ELSE 0 END) [Published] 
FROM Faculty 
INNER JOIN School ON Faculty.FacultyID = School.[FacultyID]
INNER JOIN Researcher ON School.SchoolID = Researcher.SchoolID
INNER JOIN ResearcherSubmission ON Researcher.ResearcherID = ResearcherSubmission.ResearcherID 
INNER JOIN SUBMISSION ON Submission.SubmissionID = ResearcherSubmission.SubmissionID 
GROUP BY DATENAME( MONTH,(Submission.SubmissionDate)) 
ORDER BY DATEPART( MONTH,(Submission.SubmissionDate))

Answer 2

一个简单的选择是将MONTH(Submission.SubmissionDate)添加到您的group by子句中，并将order by添加到其中：

SELECT  DATENAME( MONTH,(Submission.SubmissionDate)) AS [Date]        
FROM Submission 
GROUP BY MONTH(Submission.SubmissionDate), DATENAME( MONTH,(Submission.SubmissionDate))
ORDER BY MONTH(Submission.SubmissionDate)

这也适用于您的真实查询。

Answer 3

您可以使用MIN()或MAX()：

SELECT  DATENAME(MONTH,(Submission.SubmissionDate)) AS [Date]        
FROM Submission 
GROUP BY DATENAME(MONTH,(Submission.SubmissionDate))
ORDER BY MIN([Date]) ASC;

这会从每个组中选择一个任意日期，然后按顺序排序。

顺便说一句，你可能应该关心年份和月份。如果是这样的话：

SELECT YEAR(s.SubmissionDate), DATENAME(MONTH, s.SubmissionDate) AS [Date]        
FROM Submission s
GROUP BY YEAR(s.SubmissionDate), DATENAME(MONTH, s.SubmissionDate)
ORDER BY MIN([Date]) ASC;

按升序排序月份

3 个答案: