Question

我制作了一个二维数组，需要将元素[i][j] = 0,1,2,3,4,或5映射到要打印的彩色像素。这就是我所拥有的。

像素数组，表示不同颜色的整数值

    static int [][] marioArray = new int [][]{
    {0,0,0,0,0,1,1,1,1,1,0,0,0,0,0,0},
    {0,0,0,0,1,1,1,1,1,1,1,1,1,0,0,0},
    {0,0,0,0,2,2,2,3,3,4,3,0,0,0,0,0},
    {0,0,0,2,3,2,3,3,3,4,3,3,3,0,0,0},
    {0,0,0,2,3,2,2,3,3,3,4,3,3,3,0,0},
    {0,0,0,0,2,3,3,3,3,4,4,4,4,0,0,0},
    {0,0,0,0,0,3,3,3,3,3,3,0,0,0,0,0},
    {0,0,0,0,1,1,5,1,1,5,1,1,0,0,0,0},
    {0,0,0,1,1,1,5,1,1,5,1,1,1,0,0,0},
    {0,0,1,1,1,1,5,5,5,5,1,1,1,1,0,0},
    {0,0,3,3,1,5,3,5,5,3,5,1,3,3,0,0},
    {0,0,3,3,3,5,5,5,5,5,5,3,3,3,0,0},
    {0,0,3,3,5,5,5,5,5,5,5,5,3,3,0,0},
    {0,0,0,0,5,5,5,0,0,5,5,5,0,0,0,0},
    {0,0,0,2,2,2,0,0,0,0,2,2,2,0,0,0},
    {0,0,2,2,2,2,0,0,0,0,2,2,2,2,0,0}};

打印像素的方法

public static void drawPixl (Graphics g, int x, int y, int scale, Color color)
{
    g.setColor(color);
    g.fillRect(x,y,scale,scale);
}

我尝试使用我的数组进行for循环

    public static void drawMario (Graphics g, int x, int y, int scale)
    {
        int i;
        for(i = 0, i < 16, i++){
            int j;
            for(j = 0, j <16, j++){
            if (marioArray[i][j] == 1){
                drawPixl(g,scale*i,scale*j,scale,Color.red);}
            if (marioArray[i][j] == 2){
                drawPixl(g,scale*i,scale*j,scale,new Color(94, 38, 18));}
            if (marioArray[i][j] == 3){
                drawPixl(g,scale*i,scale*j,scale,new Color(255, 193, 37));}
            if (marioArray[i][j] == 4){
                drawPixl(g,scale*i,scale*j,scale,Color.black);}
            if (marioArray[i][j] == 5){
                drawPixl(g,scale*i,scale*j,scale,Color.blue);}
            else;
            }
        }
    }

我尝试了一个嵌套的for循环，一个增强的for循环和一个while循环，但我没有运气，我猜

修改

我测试了drawPixl()，它运行正常。 drawMario中每个for循环旁边都会弹出唯一的错误，其中包含：

 1. Syntax error on token '<', ( expected

 2. Syntax error, insert ';;) Statement' to complete ForStatement

 3. the method i(int, int) is undefined for the type Animation

此外，int scale用于定位像素的位置并为其提供正确的大小

Answer 1

在for循环中使用分号：

int i;
for(i = 0; i < 16; i++){
    int j;
    for(j = 0; j <16; j++){

Answer 2

public static void drawMario (Graphics g, int x, int y, int scale)
{
    int i;
    //for(i = 0, i < 16, i++){  --> HERE IS THE ERROR, YOU NEED TO ADD ; AFTER  0 AND 16
      for(i = 0; i < 16; i++){ // --> AFTER ADDING ;
        int j;
        //for(j = 0, j <16, j++){  --> HERE IS THE ERROR, YOU NEED TO ADD ; AFTER 0 AND 16
          for(j = 0; j <16; j++){ // --> AFTER ADDING ;
        if (marioArray[i][j] == 1){
            drawPixl(g,scale*i,scale*j,scale,Color.red);}
        if (marioArray[i][j] == 2){

Answer 3

我会采用更有活力的方法。在这里，您将永远不会获得AOB异常，并且您不必在输入数组大小更改时更改循环参数。

for(int i = 0; i < marioArray.length; i++){
    int [] row = marioArray[i];
    for(int j = 0; j <row.length; j++){
        Color color = null;
        switch(row[j]){
            case 1:
               color = Color.red; break;
            case 2: 
               color = Color(94, 38, 18); break;
              ...
         }
         if(color!=null){
           drawPixl(g,scale*i,scale*j,scale,color);
         }
  }
}

您的代码更干净，在switch语句中您只能选择Color，因此您不必将整个drawPixl方法复制到每一行。

在Java中，您不必在循环之外声明循环索引，除非您在循环之外以某种方式需要它。

Java For Loop with Array

3 个答案: