MySql以单行显示详细信息

Question

我有一个查询，它返回多行中的特定用户数据，如下所示

上面的查询结果如下，

SELECT user_id，route_id，route_schedule_id FROM um.user_rm.route WHERE user_id IN （    SELECT UR.user_id FROM um.user_rm.route UR              INNER JOIN um.user_waitinglist UW ON UW.user_id = UR.user_id              WHERE UR.route_schedule_id = 43 ）;

我的要求是将详细信息排在单行中，如下所示

任何建议，

提前致谢 桑杰塔

Answer 1

试试这个

SELECT user_id, route_id, CAST(GROUP_CONCAT(route_schedule_id) AS CHAR) AS schedules
FROM um.user_rm.route
WHERE user_id IN (
    SELECT UR.user_id
    FROM um.user_rm.route UR
    INNER JOIN um.user_waitinglist UW ON UW.user_id=UR.user_id WHERE UR.route_schedule_id=43
)
GROUP BY user_id

Answer 2

我成功完成了查询并根据需要获得了输出。以下是我的查询，

SELECT R1.user_id,R1.route_id AS Route1,R1.route_schedule_id AS Schedule1,
       R2.route_id AS Route2,R2.route_schedule_id AS Schedule2 FROM `um.user_rm.route` R1 
INNER JOIN `um.user_rm.route` R2 ON R1.user_id=R2.user_id AND R1.user_route_id > R2.user_route_id
WHERE R1.user_id  IN
(
  SELECT UR.user_id FROM `um.user_rm.route` UR
             INNER JOIN `um.user_waitinglist` UW ON UW.user_id=UR.user_id
             WHERE UR.route_schedule_id=43
)
GROUP BY R1.user_id