Question

我正在寻找一个雄辩的声明，它会给我每个room_id的最大值（时间戳），因为该room_id的所有时间戳值都超过了15天。（基本上任何在过去15天内都没有清理的房间......）

maintenancelog

+----+-------------------+---------+---------------------+
| id | maintenance_value | room_id |      timestamp      |
+----+-------------------+---------+---------------------+
|  1 | Cleaned           |       1 | 2015-09-06 00:54:59 |
|  2 | Cleaned           |       1 | 2015-09-07 01:55:59 |
|  3 | Cleaned           |       2 | 2015-09-06 02:56:59 |
|  4 | Cleaned           |       2 | 2015-09-16 03:57:59 |
|  5 | Cleaned           |       3 | 2015-09-06 04:58:59 |
|  6 | Cleaned           |       3 | 2015-09-07 05:59:59 |
+----+-------------------+---------+---------------------+

我很讨厌MySQL，但这相当于......的陈述......

select room_id,max(timestamp) from maintenancelog
group by room_id
having max(timestamp) < sysdate - 15;

雄辩的陈述应该基本上返回以下内容。

1, 2015-09-07 01:55:59
3, 2015-09-07 05:59:59

我试过......

$dt = Carbon::now();
$checkdate = $dt->subDays(15);
return $this->groupBy('room_id')->max('timestamp')->having('timestamp','<',$checkdate);

但是

Call to a member function having() on string

尝试......

return $this->groupBy('room_id')->havingRaw("max(timestamp)<sysdate()-15");

只返回时间戳早于15的所有行，忽略其他最大值......

Answer 1

max（）就像count（）是eloquent中的最终函数，代替get（）。你真正想要的是select中的max（）作为原始语句。

return $this->select(DB::raw('room_id, max(`timestamp`) as `timestamp`'))
    ->groupBy('room_id')
    ->having('timestamp','<',$checkdate)
    ->get();

Laravel eloquent结合max（）和where（）或有（）

1 个答案: