Question

我需要添加一个用户按下的按钮来启动Tkinter.askdirectory，并能够捕获结果。我已经尝试了很多例子，但是在我的特定情况下找不到任何可以成功运行的东西（我是新手并不知道我在做什么的情况：）

我已经评论了我所做的事情，因此原始代码仍然有用，所以你可以看看我一直在尝试什么。由于我与Tk在一个不熟悉的领域，这大部分都不起作用。非常感谢任何帮助。

#!/usr/bin/env python

import Tkinter
from Tkinter import *
import Tkinter, tkFileDialog

class Values(Tkinter.Tk):
    """docstring for Values"""
    def __init__(self, parent):
        Tkinter.Tk.__init__(self,parent)
        self.parent = parent
        self.initialize()

    def initialize(self):
        self.grid()
        stepOne = Tkinter.LabelFrame(self, text=" Create A Playlist ")
        stepOne.grid(row=0, columnspan=7, sticky='W',padx=5, pady=5, ipadx=5, ipady=5)
#         self.getAdir = tkFileDialog.askdirectory(parent=stepOne, title='Please select a directory')


        self.Val1Lbl = Tkinter.Label(stepOne,text="Playlist Name")
        self.Val1Lbl.grid(row=0, column=0, sticky='E', padx=10, pady=2)   
        self.Val1Txt = Tkinter.Entry(stepOne)
        self.Val1Txt.grid(row=0, column=1, columnspan=4, pady=2, sticky='WE')

        self.Val2Lbl = Tkinter.Label(stepOne,text="Task")
        self.Val2Lbl.grid(row=1, column=0, sticky='E', padx=10, pady=2)
        self.Val2Var = StringVar()    
        self.Val2Txt = Tkinter.OptionMenu(stepOne, self.Val2Var, 'Layout','Anim Pass 1','Anim Pass 2', 'Lighting', 'Compositing')
        self.Val2Txt.grid(row=1, column=1, columnspan=4, pady=2, sticky='WE')

        self.Val3Lbl = Tkinter.Label(stepOne,text="Description")
        self.Val3Lbl.grid(row=2, column=0, sticky='E', padx=10, pady=2)  
        self.Val3Txt = Tkinter.Entry(stepOne)
        self.Val3Txt.grid(row=2, column=1, columnspan=4, pady=2, sticky='WE')

#         self.Val4Lbl = Tkinter.Label(stepOne,text="Directory")
#         self.Val4Lbl.grid(row=3, column=0, sticky='E', padx=10, pady=2)
#         self.Val4Var = StringVar()
#         self.Val4Var = Tkinter.Button(command=getAdir)
#         self.Val4Txt.grid(row=3, column=1, columnspan=4, pady=2, sticky='WE')


        self.val1 = None
        self.val2 = None
        self.val3 = None
#         self.val4 = None

        SubmitBtn = Tkinter.Button(stepOne, text="Submit",command=self.submit)
        SubmitBtn.grid(row=4, column=3, sticky='W', padx=5, pady=2)

    def submit(self):
        self.val1=self.Val1Txt.get()
        if self.val1=="":
            Win2=Tkinter.Tk()
            Win2.withdraw()

        self.val2=self.Val2Var.get()
        if self.val2=="":
            Win2=Tkinter.Tk()
            Win2.withdraw()

        self.val3=self.Val3Txt.get()
        if self.val3=="":
            Win3=Tkinter.Tk()
            Win3.withdraw()

#         self.val4=self.Val4Var.get()
#         if self.val4=="":
#             Win4=Tkinter.Tk()
#             Win4.withdraw()


    self.quit()


if __name__ == '__main__':
    app = Values(None)
    app.title('Bulk Movie Upload')
    app.mainloop() #this will run until it closes
    #Print the stuff you want.
    print app.val1,app.val2,app.val3 #,app.val4

这是修改后的代码，从我认为你的意思，但仍然有错误，因为它没有传递变量。我编辑了这篇文章和代码，以简化。

    #!/usr/bin/env python

    import Tkinter
    from Tkinter import *
    import Tkinter, tkFileDialog

    class Values(Tkinter.Tk):
        """docstring for Values"""
        def __init__(self, parent):
            Tkinter.Tk.__init__(self,parent)
            self.parent = parent
            self.initialize()

        def getAdir(self):
            self.val5 = tkFileDialog.askdirectory(parent=self, title='Please select a directory')



        def initialize(self):
            self.grid()
            stepOne = Tkinter.LabelFrame(self, text=" Create A Playlist ")
            stepOne.grid(row=1, columnspan=8, sticky='W',padx=5, pady=5, ipadx=5, ipady=5)

            self.Val5Lbl = Tkinter.Label(stepOne,text="Select Folder Containing Movies")
            self.Val5Lbl.grid(row=4, column=0, sticky='E', padx=5, pady=2)
            self.Val5Var = StringVar()    
            self.Val5Txt = Tkinter.Button(stepOne, text="Select Files", command=self.getAdir)
            self.Val5Txt.grid(row=4, column=1, columnspan=4, pady=2, sticky='WE')

            self.val5 = None

            SubmitBtn = Tkinter.Button(stepOne, text="Submit",command=self.submit)
            SubmitBtn.grid(row=6, column=3, sticky='W', padx=5, pady=2)

        def submit(self):
            self.val5=self.Val5Var.get()
            if self.val5=="":
                Win2=Tkinter.Tk()
                Win2.withdraw()


        self.quit()

if __name__ == '__main__':
    app = Values(None)
    app.title('Bulk Movie Upload')
    app.mainloop() #this will run until it closes
    #Print the stuff you want.
    print "Folder is - " + app.val5

Answer 1

一个大问题是您正在创建多个Tk实例。你不能这样做。如果您需要更多窗口，请在Toplevel创建实例。

要调用函数来请求目录，您需要创建一个函数，并将该函数与按钮联系起来。你在做什么实际上是在创建其他小部件之前调用该函数，而不是等待按下按钮。

def getAdir(self):
   self.val4 = tkFileDialog.askdirectory(parent=stepOne, title='Please select a directory')

...
self.Val4Var = Tkinter.Button(self, command=self.getAdir)

注意：在我写完上述内容后，问题被更改为包含不同的代码。以下是我对该代码的评论：

在修改后的代码中，您没有按照我在答案中建议的那样做。您需要删除这行代码：

self.val5=self.Val5Var.get()

这是因为self.val5已经包含从askdirectory返回的目录。它将是一个字符串，而不是某种具有get方法的对象。

您还会遇到打开多个根窗口的问题。这将导致其他问题。

从按钮生成askdirectory

1 个答案: