Question

我正在尝试使用正则表达式从（C＃）字符串中提取引号包装的字符串，该字符串是以逗号分隔的此类字符串列表。我需要提取所有正确引用的子串，并忽略那些缺少引号的那些

例如，给这个字符串

＆＃34;动物，狗，猫＆＃34;，＆＃34;大肠杆菌，验证，＆＃34;链球菌＆＃34;

我需要提取动物，狗，猫等＃34;和＆＃34;链球菌＆＃34;。

我已经在这个论坛中尝试了各种正则表达式解决方案，但他们似乎都只找到了第一个子字符串，或者错误地匹配了＃ecoli，验证，＆＃34;并忽略＆＃34;链球菌＆＃34;

这可以解决吗？

TIA

Answer 1

试试这个：

string input = "\"animal,dog,cat\",\"ecoli, verification,\"streptococcus\"";
string pattern = "\"([^\"]+?[^,])\"";

var matches = Regex.Matches(input, pattern);

foreach (Match m in matches)
    Console.WriteLine(m.Groups[1].Value);

P.S。但我同意评论员的观点：修复来源。

Answer 2

我建议：

"(?>[^",]*(?>,[^",]+)*)"

<强>解释

"        # Match a starting quote
(?>      # Capture in an atomic group to avoid catastrophic backtracking:
 [^",]*  # - any number of characters except commas or quotes
 (?>     # - optionally followed by another (atomic) group:
  ,      #   - which starts with a comma
  [^",]+ #   - and contains at least one character besides comma or quotes.
 )*      # - (as said above, that group is optional but may occur many times)
)        # End of the outer atomic group
"        # Match a closing quote

测试live on regex101.com。

正则表达式 - 如何匹配多个正确引用的子串

2 个答案: