Question

我试图跳过并采取元素......这是我的尝试：

public function orderWhat($what){
           $this->what = $what;
           //QUERY FOR GROUPS AND PRODJECT_GROUP
           $userCondition = function($q){
                        $q->where('user_id',Auth::id())->where('project_id',$this->id)->take(10)->skip(10);
                    };

           //QUERY FOR COMMENTS AND PROJECT_COMMENT     
           $commentsCondition = function($q){
                        $q->where('project_id',$this->id)->where('order',$this->what)->orderBy('comment.id', 'DESC')->take(10)->skip(10);
                    };

                    $limit = function($q){
                        $q->take(10);
                    };
           //RETURN PROJECT WITH COMMENTS        
           $results = Project::with(['comments' => $commentsCondition,'groups' => $userCondition])
                                ->whereHas('groups', $userCondition)
                                ->whereHas('comments', $commentsCondition)

                                ->get();
           return $results;
       }

这将导致此查询，但我不会得到任何结果......

SQL：从projects中选择*其中（从groups中选择计数（） project_group上的内部联接groups。id = project_group。group_id其中project_group。project_id = projects。id和user_id = 1且project_id = 1限制10偏移 10）＆gt; = 1和（从comments内连接中选择计数（） project_comment上的comments。id = project_comment。comment_id 其中project_comment。project_id = projects。id和 project_id = 1和order = 0订单comment。id desc limit 10 偏移10）＆gt; = 1

如果我删除offset，它只需要10个帖子....

抵消不与Laravel关系[Laravel 5]

0 个答案: