我使用的是使用ike的openfiledailog框,但我想在不使用Microsoft.Win32参考的情况下执行相同的功能
Microsoft.Win32.OpenFileDialog dlg = new Microsoft.Win32.OpenFileDialog();
dlg.DefaultExt = ".png";
dlg.Filter = "JPEG Files (*.jpeg)|*.jpeg|PNG Files (*.png)|*.png|JPG Files (*.jpg)|*.jpg|GIF Files (*.gif)|*.gif";
//Nullable<bool> result =
dlg.ShowDialog();
答案 0 :(得分:2)
选项1
您可以创建自己的对话框,显示文件列表并让用户选择文件。
选项2
您可以改为使用GetOpenFileName
:
[DllImport("comdlg32.dll", SetLastError = true, CharSet = CharSet.Auto)]
static extern bool GetOpenFileName([In, Out] OpenFileName ofn);
以下是您需要的工作样本:
[DllImport("comdlg32.dll", SetLastError = true, CharSet = CharSet.Auto)]
static extern bool GetOpenFileName([In, Out] OpenFileName ofn);
[StructLayout(LayoutKind.Sequential, CharSet = CharSet.Auto)]
public class OpenFileName
{
public int structSize = 0;
public IntPtr dlgOwner = IntPtr.Zero;
public IntPtr instance = IntPtr.Zero;
public String filter = null;
public String customFilter = null;
public int maxCustFilter = 0;
public int filterIndex = 0;
public String file = null;
public int maxFile = 0;
public String fileTitle = null;
public int maxFileTitle = 0;
public String initialDir = null;
public String title = null;
public int flags = 0;
public short fileOffset = 0;
public short fileExtension = 0;
public String defExt = null;
public IntPtr custData = IntPtr.Zero;
public IntPtr hook = IntPtr.Zero;
public String templateName = null;
public IntPtr reservedPtr = IntPtr.Zero;
public int reservedInt = 0;
public int flagsEx = 0;
}
private void OpenButton_Click(object sender, EventArgs e)
{
OpenFileName openFileName = new OpenFileName();
openFileName.structSize = Marshal.SizeOf(openFileName);
openFileName.filter = "JPEG Files (*.jpeg)\0*.jpeg\0PNG Files (*.png)\0*.png\0JPG Files (*.jpg)\0*.jpg\0GIF Files (*.gif)\0*.gif\0";
openFileName.file = new String(new char[256]);
openFileName.maxFile = openFileName.file.Length;
openFileName.fileTitle = new String(new char[64]);
openFileName.maxFileTitle = openFileName.fileTitle.Length;
openFileName.title = "Open";
openFileName.defExt = "png";
if (GetOpenFileName(openFileName))
{
MessageBox.Show(openFileName.file);
}
}