Question

这些是我的两个对象

     var obj1={"firstName":"john","lastName":"Peter","email":"rasheed@gmail.com"}
var obj2={"firstName":"john","lastName":"Peter","email":"rasheed@gmail.com","address":"New York"}

obj1是动态的，我们不知道第一个作为属性的内容，如果obj1属性与值一起存在于obj2属性中，我想返回true，并且如果obj2中不存在任何一个具有其值的对象属性，那么它应该如何做到这一点，你们有什么想法吗？

Answer 1

你可以使用像lodash这样的库来做这件事，但是如果你想要一个简单易行的答案，你可以这样做（因为“Object.keys”而没有在ie8上工作）：

var equal = true;
if(Object.keys(obj1).length == Object.keys(obj2).length)
  for(i in obj1){
    if(typeof(obj2[i]) == 'undefined') equal = false;
  }
else equal = false;
console.log(equal);

Answer 2

将两个对象混合在一起，看看结果是否等于你要检查的结果：

function check(obj1, obj2){
    var obj3 = angular.extend({}, obj2, obj1);

    return angular.equals(obj3, obj2);
}

JSfiddle显示结果：http://jsfiddle.net/0p59ya5a/

var obj1={"firstName":"john","lastName":"Peter","email":"rasheed@gmail.com"}
var obj2={"firstName":"john","lastName":"Peter","email":"rasheed@gmail.com","address":"New York"}

console.log(check(obj1, obj2)); //true

var obj3={"firstName":"john","lastName":"Peter","email":"rasheed@gmail.com"}
var obj4={"firstName":"john","lastName":"Peter","address":"New York"}

console.log(check(obj3, obj4)); //false

var obj1={"firstName":"john","lastName":"Peter","email":"rasheed@gmail.com"}
var obj2={"firstName":"jim","lastName":"Peter","email":"rasheed@gmail.com","address":"New York"}

console.log(check(obj5, obj6)); //false

如果我给出的所有对象属性都存在于其他对象中，如何返回true

2 个答案: