SQL - 使用多个条件加入

Question

我有3张桌子：

食谱：id - name

条件：id - name

recipe_has_criterias ：id - id_recipe - id_criteria

例如，在 recipe_has_criterias ：

中

1 - 1 - 1

2 - 1 - 2

3 - 2 - 1

我想获得标准1和2的配方（这里的食谱为id 1）

我该怎么做？

感谢您的帮助

Answer 1

select r.name
from recipe r
join recipe_has_criterias rc on r.id = rc.id_recipe
where rc.id_criteria in (2,3)
group by r.name
having count(distinct rc.id_criteria) = 2

Answer 2

select a.*,b.*,c.*
from recipe_has_criterias a
inner join recipe b
on b.id=a.id_recipe
inner join criteria c
on c.id=a. id_criteria and a. id_criteria in(2,3)

Answer 3

执行2个连接，每个标准对应一个： -

SELECT r.name
FROM recipe r
INNER JOIN recipe_has_criteria rc1
ON r.id = rc1.id_recipe
INNER JOIN recipe_has_criteria rc2
ON r.id = rc2.id_recipe
WHERE rc1.id_criteria = 2
AND rc2.id_criteria = 3