Question

在我的下面列表中，我显示了所有类别，但子类别不显示名称。子类别名称应显示为

Example
Example > Some Example 1
Example > Some Example 2
PHP
PHP > Functions

问题：在我的模型上，我应该能够检索子类别名称和父类别名称。但不行。只能显示父图像，如图像所示，我使用组连接，但它不显示在列表组中，concat应显示为＆gt;当子猫名称在那里时。

为什么它不起作用，什么是最佳解决方案？

如图所示，不显示> Some Example 1。

在我的模型上，我使用多个连接表，例如.c1和.cd1获取父类别，.cd2 .c2获取子类别。

但是，当我使用我的db-＆gt;选择Group Concat时，它不起作用，只获取父类别名称。

public function get_categories() {
    $language_id = '1';

    $this->db->select('cp.category_id AS category_id, GROUP_CONCAT(cd1.name SEPARATOR "&nbsp;&gt;&nbsp;") as name');
    $this->db->from('category_path cp', 'LEFT');

    // Parent Cat
    $this->db->join('category c1', 'c1.category_id = cp.category_id', 'LEFT');

    // Sub Cat
    $this->db->join('category c2', 'c2.category_id = cp.path_id', 'LEFT'); 

    // Parent Cat
    $this->db->join('category_description cd1', 'cd1.category_id = cp.path_id', 'LEFT');

    // Sub Cat
    $this->db->join('category_description cd2', 'cd2.category_id = cp.category_id', 'LEFT');

    $this->db->group_by('cp.category_id');
    $this->db->order_by('name', 'ASC');
    $this->db->where('cd1.language_id', (int)$language_id);
    $this->db->where('cd2.language_id', (int)$language_id);
    $query = $this->db->get();

    return $query->result_array();

}

在下面尝试使用false而不是同样的结果

$this->db->select('cp.category_id AS category_id, GROUP_CONCAT(cd1.name SEPARATOR "&nbsp;&nbsp;&gt;&nbsp;&nbsp;") as name', false);

Var结果转储

array(5) { [0]=> array(2) { ["category_id"]=> string(2) "19" ["name"]=> string(7) "Example" } [1]=> array(2) { ["category_id"]=> string(2) "22" ["name"]=> string(7) "Example" } [2]=> array(2) { ["category_id"]=> string(2) "25" ["name"]=> string(7) "Example" } [3]=> array(2) { ["category_id"]=> string(2) "23" ["name"]=> string(3) "PHP" } [4]=> array(2) { ["category_id"]=> string(2) "24" ["name"]=> string(3) "PHP" } }

最后查询

SELECT `cp`.`category_id` AS `category_id`, GROUP_CONCAT(cd1.name ORDER BY level SEPARATOR " > ") as name FROM `category_path` `cp` LEFT JOIN `category` `c1` ON `c1`.`category_id` = `cp`.`category_id` LEFT JOIN `category` `c2` ON `c2`.`category_id` = `cp`.`path_id` LEFT JOIN `category_description` `cd1` ON `cd1`.`category_id` = `cp`.`path_id` LEFT JOIN `category_description` `cd2` ON `cd2`.`category_id` = `cp`.`category_id` WHERE `cd1`.`language_id` = 1 AND `cd2`.`language_id` = 1 GROUP BY `cp`.`category_id` ORDER BY `name` ASC

类别表

类别说明表

类别路径表

Answer 1

试试这个：

$this->db->select("cp.category_id AS category_id, GROUP_CONCAT(cd1.name ORDER BY cp.level SEPARATOR '&nbsp;&nbsp;&gt;&nbsp;&nbsp;') AS name, c1.parent_id, c1.sort_order", FALSE);

$this->db->select()接受可选的第二个参数。如果将其设置为FALSE，CodeIgniter将不会尝试使用反引号来保护您的字段或表名称。如果您需要复合选择语句，这非常有用。

Answer 2

感谢所有愿意提供帮助的人。

我发现问题的原因在于我的添加类别功能。

如果我是category_path表格中的子类别，我什么时候创建一个类别

如果子类别ID是22和父ID 19

然后在category_path表中，行应该有两行插入两行，如下所示。

category_id  path_id  level
22           19        0
22           22        1

由于某些原因，我的模型添加类别功能，它没有插入路径ID正确

现在我知道需要修复模型功能。

完整工作模式

<?php

class Model_category extends CI_Model {

    public function add() {
        $data = array(
            'parent_id' => (int)$this->input->post('parent_id'),
            'status' => $this->input->post('status'),
            'date_edited' => mdate('%Y-%m-%d %H:%i:%s', now()),
            'date_added' => mdate('%Y-%m-%d %H:%i:%s', now())
        );

        $this->db->insert($this->db->dbprefix . 'category', $data);

        $category_id = $this->db->insert_id();

        $data = array(
            'category_id' => (int)$category_id,
            'language_id' => (int)'1',
            'name' => $this->input->post('name'),
            'meta_title' => $this->input->post('meta_title'),
            'meta_description' => $this->input->post('meta_description'),
            'meta_keyword' => $this->input->post('meta_keyword'),
            'date_edited' => mdate('%Y-%m-%d %H:%i:%s', now()),
            'date_added' => mdate('%Y-%m-%d %H:%i:%s', now())
        );

        $this->db->insert($this->db->dbprefix . 'category_description', $data);

        // MySQL Hierarchical Data Closure Table Pattern

        $level = 0;

        $this->db->select('*');
        $this->db->from($this->db->dbprefix . 'category_path');
        $this->db->where('category_id', (int)$this->input->post('parent_id'));
        $this->db->order_by('level', 'ASC');
        $query = $this->db->get();

        foreach ($query->result_array() as $result) {

            $data = array(
                'category_id' => (int)$category_id,
                'path_id' => (int)$result['path_id'],
                'level' => (int)$level,
            );

            $this->db->insert($this->db->dbprefix . 'category_path', $data);

            $level++;
        }

       // The problem was here was not adding category into model but now
       // All Fixed.

        $data = array(
            'category_id' => (int)$category_id,
            'path_id' => (int)$category_id,
            'level' => (int)$level
        );

        $this->db->insert($this->db->dbprefix . 'category_path', $data);

        if (isset($data['keyword'])) {
            $data = array(
                'category_id' => 'category_id=' . (int)$category_id,
                'keyword' => $this->input->post('keyword'),
                'date_edited' => mdate('%Y-%m-%d %H:%i:%s', now()),
                'date_added' => mdate('%Y-%m-%d %H:%i:%s', now())
            );

            $this->db->insert($this->db->dbprefix . 'url_alias', $data);

            $this->db->query("INSERT INTO " . $this->db->dbprefix . "url_alias SET query = 'category_id=" . (int)$category_id . "', keyword = '" . $this->db->escape($data['keyword']) . "'");
        }

    }

    public function edit() {
    }


    public function get_categories($data = array()) {
        $language_id = '1';
        $this->db->select('cp.category_id AS category_id, GROUP_CONCAT(cd1.name ORDER BY level SEPARATOR " > ") as name, c1.parent_id, c1.sort_order');
        $this->db->distinct();
        $this->db->from($this->db->dbprefix . 'category_path cp', 'LEFT');
        $this->db->join($this->db->dbprefix . 'category c1', 'cp.category_id = c1.category_id', 'LEFT');
        $this->db->join($this->db->dbprefix . 'category c2', 'cp.path_id = c2.category_id', 'LEFT');
        $this->db->join($this->db->dbprefix . 'category_description cd1', 'cp.path_id = cd1.category_id', 'LEFT');
        $this->db->join($this->db->dbprefix . 'category_description cd2', 'cp.category_id = cd2.category_id', 'LEFT');
        $this->db->where('cd1.language_id', '1');
        $this->db->where('cd2.language_id', '1');
        $this->db->group_by('cp.category_id');
        $this->db->order_by('name', 'ASC');
        $query = $this->db->get();
        if ($query->num_rows() > 0) {
            return $query->result_array();

        } else {
            return FALSE;
        }
    }
}

Codeigniter多次加入没有获得Sub Cat＆＃34;名称＆＃34;与Group_Concat

2 个答案: