Question

我想询问是否有可能SELECT * INTO特定订单中的新表格？

这是我的SQL语句：

SELECT * INTO TEMP FROM (

SELECT a.Name, b.Balance, -c.AmountOut as amount, c.Date
FROM Item a, Stock b, StockOut c
WHERE a.ID = b.ItemID AND b.ID = c.StockID

UNION

SELECT a.Name, b.Balance, -c.AmountIn as amount, c.Date
FROM Item a, Stock b, StockIn c
WHERE a.ID = b.ItemID AND b.ID = c.StockID

//PLACE 1: ORDER BY DATE STATEMENT

) As Temp //PLACE 2: ORDER BY DATE STATEMENT

基本上我希望在输入数据库时以升序日期顺序输入库存中的所有库存，因为我想根据要在图表中绘制的日期来执行运行总计。但似乎两个地方都不正确。

我的脚本如下：

ALTER TABLE TEMP ADD SIndex INT identity(1,1)
ALTER TABLE TEMP ADD RunningTotal INT

SELECT ... , (SELECT SUM(amount) FROM TEMP b WHERE b.SIndex >= a.SIndex AND b.Name = a.Name)
FROM TEMP a

您可以看到日期的顺序很重要，否则运行总计会出错。所以我想知道是否还有确保SELECT * INTO声明可以有一定的顺序？

非常感谢！

Answer 1

如果您的标识列的顺序相关，请使用ROW_NUMBER()例如

创建您自己的标识

SELECT  SIndex = ROW_NUMBER() OVER(ORDER BY Date), *
INTO    Temp
FROM    (   
            SELECT a.Name, b.Balance, -c.AmountOut as amount, c.Date
            FROM Item a, Stock b, StockOut c
            WHERE a.ID = b.ItemID AND b.ID = c.StockID

            UNION

            SELECT a.Name, b.Balance, -c.AmountIn as amount, c.Date
            FROM Item a, Stock b, StockIn c
            WHERE a.ID = b.ItemID AND b.ID = c.StockID
        ) AS temp;

或先创建临时表，然后使用INSERT INTO .... SELECT维护您的订单。

有一个IDENTITY()函数，允许您在插入时生成标识列，e.generate

SELECT  SIndex = IDENTITY(), *
INTO    Temp
FROM ....

然而。这样做 NOT 保证身份的顺序与插入的顺序相符。

除了唯一标识行之外，标识列不应该具有任何其他含义，如果它们具有任何含义，则它们未被正确使用。插入新行后，您的“标识”列将不再显示日期顺序。我倾向于不打扰临时表：

WITH Temp AS
(   SELECT  SIndex = ROW_NUMBER() OVER(ORDER BY Date), *
    FROM    (   
                SELECT a.Name, b.Balance, -c.AmountOut as amount, c.Date
                FROM Item a, Stock b, StockOut c
                WHERE a.ID = b.ItemID AND b.ID = c.StockID

                UNION

                SELECT a.Name, b.Balance, -c.AmountIn as amount, c.Date
                FROM Item a, Stock b, StockIn c
                WHERE a.ID = b.ItemID AND b.ID = c.StockID
            ) AS temp
)
SELECT  RunningTotal = (    SELECT SUM(amount) 
                            FROM    TEMP AS b 
                            WHERE   b.SIndex >= a.SIndex 
                            AND     b.Name = a.Name)
FROM    TEMP AS a;

或者，如果您使用的是SQL Server 2012或更高版本，只需：

WITH Temp AS
(   SELECT  SIndex = ROW_NUMBER() OVER(ORDER BY Date), *
    FROM    (   
                SELECT a.Name, b.Balance, -c.AmountOut as amount, c.Date
                FROM Item a, Stock b, StockOut c
                WHERE a.ID = b.ItemID AND b.ID = c.StockID

                UNION

                SELECT a.Name, b.Balance, -c.AmountIn as amount, c.Date
                FROM Item a, Stock b, StockIn c
                WHERE a.ID = b.ItemID AND b.ID = c.StockID
            ) AS temp
)
SELECT  RunningTotal = SUM(amount) OVER(PARTITION BY Name ORDER BY SIndex)
FROM    Temp;

值得注意的是，如果您有两行具有相同的日期和相同的名称，则无法保证如果您运行查询两次它们将以相同的顺序结束，您可能希望考虑添加进一步订购标准。我假设会有重复，否则查询可能只是：

WITH Temp AS
(   
    SELECT a.Name, b.Balance, -c.AmountOut as amount, c.Date
    FROM Item a, Stock b, StockOut c
    WHERE a.ID = b.ItemID AND b.ID = c.StockID

    UNION

    SELECT a.Name, b.Balance, -c.AmountIn as amount, c.Date
    FROM Item a, Stock b, StockIn c
    WHERE a.ID = b.ItemID AND b.ID = c.StockID
)
SELECT  RunningTotal = (    SELECT SUM(amount) 
                            FROM    TEMP AS b 
                            WHERE   b.Date >= a.Date 
                            AND     b.Name = a.Name)
FROM    TEMP AS a;

Answer 2

希望这有效

创建表格并插入

Create table TEMPv1 
(
SIndex INT identity(1,1),
Name varchar(max),
AmountOut int,
[Date] datetime,
)

insert into TEMPv1 ( Name,AmountOut,[Date])

SELECT a.Name, b.Balance, -c.AmountOut as amount, c.Date
FROM Item a, Stock b, StockOut c
WHERE a.ID = b.ItemID AND b.ID = c.StockID

UNION

SELECT a.Name, b.Balance, -c.AmountIn as amount, c.Date
FROM Item a, Stock b, StockIn c
WHERE a.ID = b.ItemID AND b.ID = c.StockID
ORDER BY c.Date

ALTER TABLE TEMPv1 ADD RunningTotal INT

SELECT ... , (SELECT SUM(amount) FROM TEMP b WHERE b.SIndex >= a.SIndex AND     b.Name = a.Name)
FROM TEMPv1 MP a

Answer 3

Select into

无法在cmds/screencap/screencap.cpp

中使用

Please Check the Posted enquiry

SELECT * INTO基于特定订单

3 个答案: