Question

我在构建程序时收到以下错误消息：

errorC2657：二进制＆＃39;＆gt;＆gt;＆＃39;：找不到右侧的操作员类型＆＃39; const char [2]＆＃39;（或没有可接受的转换）的操作数

以下是我的程序的源代码：

#include <iostream>
#include <string> 

using namespace std;

int main()
{
int number1;
int number2;
int intSum;
int intdiff;
int intprod;
int intaver;
cout << "Enter the 1st and 2nd ODD integers (separate them by a space):     ";
cin >> number1 >>" " >> number2;
intSum = abs(number1 + number2);
intdiff = abs(number1 - number2);
intprod = abs(number1 * number2);
intaver = abs((number1 + number2) / 2);
if ( number1%2 != 0)
    cout << "You must enter ODD integers! See you next time." <<endl;
else if ( number2%2 != 0)

    cout << "You must enter ODD integers! See you next time." <<endl;
else
{
    cout << "The sum of the integers is"<<intSum<<endl;
    cout << "The difference of the integers is"<<intdiff<<endl;
    cout << "The product of the integers is"<<intprod<<endl;
    cout << "The average of the integers is"<<intaver<<endl;   
    if (number1 > number2)
        cout << "The first one "<< number1 <<" is bigger." <<endl;
    else if (number2 > number1)
        cout << "The second one "<< number2 <<" is bigger." <<endl;
    else
        cout <<"Both numbers are the same."<<endl;
    }
    return 0;
}

请帮我解决问题。我是初学者。

Answer 1

本声明：

cin >> number1 >> " " >> number2;

尝试写您的输入到number1，然后是字符串文字（const char[2]），然后是number2。这不是你想要的，特别是因为这些流足够聪明，可以自己跳过空白区域：

cin >> number1 >> number2;

您可以使用以下代码查看此内容：

#include <iostream>
int main() {
  int i1, i2;
  std::cout << "Please enter two integers: ";
  std::cin >> i1 >> i2;
  std::cout << "You entered " << i1 << " and " << i2 << '\n';
  return 0;
}

，当运行时，它起作用：

Please enter two integers:     4     77
You entered 4 and 77

Answer 2

cin >> number1 >>" " >> number2;

需要改为

cout << endl << "Enter first number : ";
cin >> number1;
cout << endl << "Enter second number : ";
cin >> number1;

>>是为cin定义为接收者的运算符，使用const char[2]类型操作数是非法的。 paxDiablo解释说，" "是const char[2]。但是，就像PaxDiablo说的那样，他的方式更好。

Answer 3

这是问题所在：

cin >> number1 >>" " >> number2;

将其拆分为两个操作：

cin >> number1;
cin >> number2;

或

cin >> number1 >> number2;

operator>>的{p> cin读取到新行或空格。因此它将处理由空格分隔的输入。

Answer 4

cin无法接受字符串文字（" "）。您需要将两个输入分开。

cin >> number1;
cin >> number2;

您还可以获取字符串并自行解析。

#include <string>
#include <boost/algorithm/string.hpp>
#include <vector>

std::string str;
cin >> str;
std::vector<std::string> strs;
boost::split(strs, "str", boost::is_any_of(" "));

int number1 = atoi(strs[0]);
int number2 = atoi(strs[1]);

c ++错误2679：二进制＆＃39;＆gt;＆gt;＆＃39; ：找不到操作员

4 个答案: