Question

我有php文件，SQL查询分为多行。例如：

$sql = "select count( aa." . BOOK_ART_ID . ") as book_count
                from " . BOOK_ART_TABLE . " as aa
                inner join " . AUTHER_TABLE . " as l on aa." . BOOK_ART_AUTHER_ID . " = l." . AUTHER_ID . " AND
                    l." . AUTHER_CODE . " = '" . "'     
                where aa." . BOOK_ART_TITLE_ID . " = " . $book_id;

我正在尝试从PHP文件中提取所有SQL语句。我在$ sql上尝试grep并且只返回第一行。

如何从所有PHP文件中提取整个SQL字符串？

我正在考虑删除换行符，直到';'字符。

Answer 1

您可以尝试此sed，

sed -n '/\$sql/{ :loop; N; s/ *\n *//g; /;/{p;q}; t loop}' yourfile

<强>测试

$ sed -n '/\$sql/{ :loop; N; s/ *\n *//g; /;/{p;q}; t loop}' yourfile
$sql = "select count( aa." . BOOK_ART_ID . ") as book_countfrom " . BOOK_ART_TABLE . " as aainner join " . AUTHER_TABLE . " as l on aa." . BOOK_ART_AUTHER_ID . " = l." . AUTHER_ID . " ANDl." . AUTHER_CODE . " = '" . "'where aa." . BOOK_ART_TITLE_ID . " = " . $book_id;

unix命令删除php命令的换行符

1 个答案: