Question

我为我的生活无法弄清楚为什么我的桌子没有显示结果。它充当值但不显示任何文本。我需要根据用户的选择只显示食物的类型。

数组

$aList = array ();
$aList[0] = array();
$aList[0]['Animal'] = "Bear";
$aList[0]['Habitat'] = "Forest";
$aList[0]['Food'] = "Meat";


$aList[1] = array();
$aList[1]['Animal'] = "Deer";
$aList[1]['Habitat'] = "Forest";
$aList[1]['Food'] = "Grass";

$aList[2] = array();
$aList[2]['Animal'] = "Pig";
$aList[2]['Habitat'] = "Farm";
$aList[2]['Food'] = "Mixed";

$aList[3] = array();
$aList[3]['Animal'] = "Cow";
$aList[3]['Habitat'] = "Farm";
$aList[3]['Food'] = "Grass";

$aList[4] = array();
$aList[4]['Animal'] = "Sheep";
$aList[4]['Habitat'] = "Farm";
$aList[4]['Food'] = "Grass";

$aList[5] = array();
$aList[5]['Animal'] = "Camel";
$aList[5]['Habitat'] = "Desert";
$aList[5]['Food'] = "Grass";

$aList[6]['Animal'] = "Scorpion";
$aList[6]['Habitat'] = "Desert";
$aList[6]['Food'] = "Meat";

功能

function showList($Food){
        // Use the global keyword to tell the PHP engine to find the variable $classList outside of the function.  Without this, the PHP engine will only look for $classList inside a function.

        global $aList;

        // Set up a variable $tbl to store the HTML output (class list table)
        // Note that the <table></table> tags and the table header row are outside of the foreach loop so that they are not repeated in each iteration of the loop.

        $tbl = "<table border=1>";
        $tbl = $tbl."<tr><th>Animal</th><th>Habitat</th><th>Food</th></tr>";

        foreach ($aList as $Animal){
            if (isset($_POST['submit'])) {
                $food = strtolower($_POST['Food']);
                    if (strtolower($Animal['Food']) == $food)
                    $tbl .= "<tr><td>{$Animal[$food.'Animal']}</td><td>{$Animal[$food.'Habitat']}</td><td>{$Animal[$food.'Food']}</td></tr>";
            }

            if (isset($_POST['submit'])) {
                $habitat = strtolower($_POST['Habitat']);
                if (strtolower($Animal['Habitat']) == $habitat)
                    $tbl .= "<tr><td>{$Animal[$habitat.'Animal']}</td><td>{$Animal[$habitat.'Habitat']}</td><td>{$Animal[$habitat.'Food']}</td></tr>";

            }

        }
    $tbl .= "</table>";
    echo $tbl;
}

Answer 1

您试图在循环中获得$Animal[$food.'Animal']的值，但在您的数组中它只是$Animal['Animal']。您正在将食物变量与键连接，但您的阵列没有任何其他键，然后是Animal，Habitat和Food。因此，您需要从$Animal数组中的键值中获取所有$ food和$ habitat变量。

无法从PHP函数中获得结果

1 个答案: