这是我的问题：将iPhone 6 Plus或iPad旋转到例如LandscapeLeft。
假设您的应用具有以下代码（仅作为示例）
override func supportedInterfaceOrientations() -> UIInterfaceOrientationMask {
return UIInterfaceOrientationMask.Portrait
// mine does use All, but with this case you'll understand my question
}
时，如何检测设备是否应使用垂直或水平布局？
func willTransitionToTraitCollection(newCollection: UITraitCollection, withTransitionCoordinator coordinator: UIViewControllerTransitionCoordinator)
被称为？
print(UIScreen.mainScreen().bounds.width < UIScreen.mainScreen().bounds.height)
// will return false, because we started in landscape but the layout will be forced to be vertical here
print(UIApplication.sharedApplication().statusBarOrientation == .LandscapeLeft)
// will return true, because we started in landscape but the layout will be forced to be vertical here
主要问题出现在iPad上，因为两个尺码类都是regular。
我很困惑，不知道如何解决这个问题。
答案 0 :(得分：0)
不要将您的布局视为垂直和水平。只需让应用程序旋转，然后响应尺寸等级或尺寸变化。
在iPad上，尽量避免使用两种布局。只需使用autolayout自动重新调整比例。但是如果你必须在iPad上响应轮换，那么回复import java.io.*;
import java.util.Scanner;
public class WordsWordsWords {
public static void main(String[] args) throws IOException {
File temp = new File("words.txt"); // Searches for the file
Scanner file = new Scanner(temp); // Creates a Scanner
int count = 0; // Finds the number of words that are in the file
while (file.hasNextLine()) // Determines how many words are in the file
{
file.nextLine();
count++;
}
file.close(); // Closes the scanner
String[] wordarr = new String[count]; // Creates an array with each element in the file
Scanner listplacement = new Scanner(temp); // Creates a scanner
for (int i = 0; i < wordarr.length; i++) // Takes each element and assigns a name to each one.
{
wordarr[i] = listplacement.nextLine();
}
listplacement.close(); // Closes the scanner
System.out.println("Your list of names (unsorted):"); // Prints out array of unordered words
for (int i = 0; i < wordarr.length; i++) {
System.out.println(wordarr[i]);
}
for (int i = 0; i < wordarr.length - 1; i++) {
int low = i;
for (int j = i + 1; j < wordarr.length; j++) {
if (wordarr[j].compareTo(wordarr[low]) < 0) {
low = j;
}
}
String tempo = wordarr[low];
wordarr[low] = wordarr[i];
wordarr[i] = tempo;
}
System.out.println();
System.out.println("Alphabetized Names:");
for (int n = 0; n < wordarr.length; n++) {
System.out.println(wordarr[n]);
}
System.out.println();
System.out.println("Names with Switched Letters");
for (int i = 0; i < wordarr.length; i++) {
String NameString = wordarr[i]; // Changes letters of the code
char[] NameChar = NameString.toCharArray();
for (int j = 0; j < NameChar.length; j++) {
if (NameChar[j] == 'A') {
NameChar[j] = 'E';
} else if (NameChar[j] == 'E') {
NameChar[j] = 'I';
} else if (NameChar[j] == 'I') {
NameChar[j] = 'O';
} else if (NameChar[j] == 'O') {
NameChar[j] = 'U';
} else if (NameChar[j] == 'U') {
NameChar[j] = 'A';
} else if (NameChar[j] == 'a') {
NameChar[j] = 'e';
} else if (NameChar[j] == 'e') {
NameChar[j] = 'i';
} else if (NameChar[j] == 'i') {
NameChar[j] = 'o';
} else if (NameChar[j] == 'o') {
NameChar[j] = 'u';
} else if (NameChar[j] == 'u') {
NameChar[j] = 'a';
}
for (j = 0; j < NameChar.length; j++) {
System.out.print(NameChar[j]);
}
}
}
}
}
（因为特征集合不会改变）。