Question

以下是我的代码。当我运行它时，它会报告所有都已关闭但不应该关闭。无法弄清楚错误在哪里

import datetime
import time
import pytz 

openingtime = ('09:00')
closingtime = ('21:00')

localtime = int(datetime.datetime.now().strftime("%H"))
localtime = ('US/Pacific')

easterntime = ('US/Eastern')
UKtime = ('Europe/London')

def checktime(localtime):
    bresult = False
    if localtime > openingtime and localtime < closingtime:
        bresult = True

    return bresult

if checktime(localtime) == True:
    print 'The Local Office is Open Now.'
else:
    print 'The Local Office is Closed Now.'

if checktime(easterntime) == True:
    print 'The East Office is Open Now.'
else:
    print 'The East Office is Closed Now.'

if checktime(UKtime) == True:
    print 'The UK Office is Open Now.'
else:
    print 'The UK Office is Closed Now.'

Answer 1

请考虑以下几行：

localtime = int(datetime.datetime.now().strftime("%H"))

localtime = ('US/Pacific')

第一行将localtime变量设置为当前小时的整数。然后第二行覆盖该变量，而是使其引用字符串＆＃39; US / Pacific＆＃39;。传递到checktime函数时，该字符串将始终比关闭时间（字符串＆＃39; 21：00＆＃39;）更大，因此checktime将始终返回False。

试图确定错误的位置

1 个答案: