Question

您好我正在尝试在function1和function2运行两个主题。我function1首先运行function1而time.sleep(1000)暂停function2。我专家function1立即与import thread import time # Define a function for the thread def function1( threadName, delay): print "%s: %s" % ( threadName, time.ctime(time.time()) ) time.sleep(1000) def function2( threadName, delay): count = 0 while count < 5: time.sleep(delay) count += 1 print "%s: %s" % ( threadName, time.ctime(time.time()) ) # Create two threads as follows try: thread.start_new_thread( function1, ("Thread-1", 2, ) ) thread.start_new_thread( function2, ("Thread-2", 4, ) ) except: print "Error: unable to start thread" while True: pass一起开始并继续运行。

 Thread-1: Tue Sep 22 19:10:03 2015

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git branch-today new_branch_name

Answer 1

你永远不会得到这种性质的真正确定性调度，但我认为这里的主要问题可能是当主线程出现时

while True:
    pass

它处于繁忙的等待状态，在此期间它将占用几乎所有可用的CPU。在Python中，即使您的计算机上有多个核心，您也只会看到一次运行一个（非IO阻塞的）线程。

如果要启动一个或多个线程然后等待它们完成，最简单的方法是使用higher-level threading interface：

from threading import Thread
t = Thread(target=function1, args=("Thread-1", 2))
# ...
t.join()  # wait for thread to exit

所有这一切，你的代码似乎表现得像你在我的机器上所期望的那样：

C:\Python27\python.exe C:/dev/python/scratch/concurrent.py
Thread-1: Tue Sep 22 13:37:51 2015
Thread-2: Tue Sep 22 13:37:55 2015
Thread-2: Tue Sep 22 13:37:59 2015
Thread-2: Tue Sep 22 13:38:03 2015
Thread-2: Tue Sep 22 13:38:07 2015
Thread-2: Tue Sep 22 13:38:11 2015

并行线程无需等待python中的其他线程

1 个答案: