Question

好吧，我已经完成了之前的一些问题，这并没有真正帮助我，因为大多数人都在使用java swing和其他远离我联盟的东西。我只需要一个基于功能控制台的tic tac toe，但我不想复制+粘贴完成的代码。到目前为止，我被困在最后一个方法makeMove。它现在要求坐标并保存变量行和输入中的输入。 col，但那又怎样？如何让棋子出现在棋盘上？此外，它不喜欢我使用行＆amp;在下一个循环中再次col，所以我不确定该怎么做。

import java.util.Scanner;

public class TTT {

    static Scanner keyboard = new Scanner(System.in);
    static int counter;
    static String player1, player2;
    static boolean gameOver = false;
    static char[][] board = new char[3][3];
    static char playerMarker;

    public static void main(String[] args) {

        setupPlayers();
        printBoard();
        setupBoard();
        makeMove();
    }

    public static void setupBoard() {
        for (int i = 0; i < 3; i++)
            for (int k = 0; k < 3; k++)
                board[i][k] = ' ';


    }

    static public void printBoard() {
        System.out.println("\n");
        System.out.println(board[0][0] + "   |" + board[0][1] + "   |" + board[0][2]);
        System.out.println("-----------");
        System.out.println(board[1][0] + "   |" + board[1][1] + "   |" + board[1][2]);
        System.out.println("-----------");
        System.out.println(board[2][0] + "   |" + board[2][1] + "   |" + board[2][2]);

    }

    public static void setupPlayers() {

        System.out.print("Player1, what's your name?: ");
        player1 = keyboard.next();
        System.out.print("Alright " + player1 + ", who's Player2?");
        player2 = keyboard.next();
        System.out.print(player1 + " versus. " + player2 + ", good luck!");
    }

    public static void makeMove()
    {
        System.out.println("Enter a row and a column: ");
        int row = keyboard.nextInt();
        int col = keyboard.nextInt();

        while (board[row][col] != ' ')
        {
            System.out.println("\nCoordinates already in use. Please try again: ");

        }
    }
}

Answer 1

有点（如果我不准）

public static void makeMove()
{
    System.out.println("Enter a row and a column: ");
    int row = keyboard.nextInt();
    int col = keyboard.nextInt();

    if (board[row][col] != ' ')
    {
        System.out.println("\nCoordinates already in use. Please try again: ");
       return;
    }
    board[row][col] = 'X' ... or '+' please code 
    printBoard();


}

编辑：Joop说计算机移动，我的答案是纠正用户移动。 Yout工作是一起收集代码：）

Answer 2

以下break使用自由命名的标签loop输出for循环。通常不应该使用标签，但这里似乎很自然。你无法打破，但寻找最好的（i，k）。

boolean found = false;
loop: for (int i = 0; i < 3; i++) {
    for (int k = 0; k < 3; k++) {
        if (board[i][k] == ' ') {
            found = true;
            row = i;
            col = j;
            break loop;
        }
    }
}

控制台tic tac toe

2 个答案: