Question

我有两个数组

$array1 = ["name1","name2","name3","name4"];
$array2 = ["name2","name1","name3","name4"];

我想知道的是阵列之间的位置变化。在上面的例子中，输出将是：

$returnArray = [
    "name2"=>"up",
    "name1"=>"down",
    "name3"=>"same",
    "name4"=>"same"
];

up =向上移动

down =向下移动

相同 =保持在同一位置

比较两个阵列确定位置变化的最快方法是什么？

Answer 1

这应该适合你：

只需循环浏览$array1的所有唯一值，然后查看array_search() 如果值处于相同位置，则向下或向上。

<?php

    $array1 = ["name1","name2","name3","name4"];
    $array2 = ["name2","name1","name3","name4"];
    $result = [];

    foreach(array_unique($array1) as $k => $v){
        $result[$v] = $k == array_search($v, $array2) ? "same" : ($k < array_search($v, $array2) ? "up": "down");
    }

    print_r($result);

?>

在PHP 7中，只需使用太空船运营商，例如

<?php

    $array1 = ["name1","name2","name3","name4"];
    $array2 = ["name2","name1","name3","name4"];
    $arr = ["-1" => "down", "0" => "same", "1" => "up"];
    $result = [];

    foreach(array_unique($array1) as $k => $v){
        $result[$v] = $arr[array_search($v, $array2) <=> $k];
    }

    print_r($result);

?>

确定两个数组

1 个答案: