Question

这是我的代码，它给了我所有数量的Android设备，如手机号码，WhatsApp号码和固定电话号码。但我只想将Android手机本中的手机号码和固定电话号码放入我的应用程序中。我如何才能获得每个联系人姓名的手机号码和固定电话号码？

private void addContactsInList() {
    // TODO Auto-generated method stub

    Cursor cursor = getContentResolver().query(
            ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
            null, null, null, null);

    try {
        ContactsListClass.phoneList.clear();
    } catch (Exception e) {

    }

    while (cursor.moveToNext()) {
        String phoneName = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
        String phoneNumber = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
        int phoneId = cursor.getInt(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.CONTACT_ID));


        Contact cp = new Contact();

        cp.setName(phoneName);
        cp.setNumber(phoneNumber);
        cp.setId(phoneId);


        ContactsListClass.phoneList.add(cp);
       // Log.e("add to list", "content" + phoneId +phoneName +phoneNumber);
    }
    cursor.close();

    lv = new ListView(context);

    lv.setLayoutParams(new LayoutParams(
            LayoutParams.MATCH_PARENT,
            LayoutParams.MATCH_PARENT));


    llContainer.addView(lv);

    Collections.sort(ContactsListClass.phoneList, new Comparator<Contact>() {
        @Override
        public int compare(Contact lhs,
                           Contact rhs) {
            return lhs.getName().compareTo(
                    rhs.getName());
        }
    });

    contactAdapter = new ContactsAdapter(MainActivity.this,
            ContactsListClass.phoneList);
    lv.setAdapter(contactAdapter);

Answer 1

在你的while循环中，输入如下内容：

    while (phoneCursor.moveToNext()) {
                phoneNumber = phoneCursor.getString(phoneCursor.getColumnIndex(NUMBER));
                //String number = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                int type = phoneCursor.getInt(phoneCursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.TYPE));
                switch (type) {
                    case ContactsContract.CommonDataKinds.Phone.TYPE_HOME:
                        // do something with the Home number here...
                        break;
                    case ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE:
                        output.append("\n Phone number:" + phoneNumber);
                        break;
                    case ContactsContract.CommonDataKinds.Phone.TYPE_WORK:
                        // do something with the Work number here...
                        break;
                }
            }

见this回答

Answer 2

试试这个，

Cursor cursor = null;
            ArrayList<String> numberList=new ArrayList<String>();
            try {
                cursor = context.getContentResolver().query(Phone.CONTENT_URI, null, null, null, null);
                int contactIdIdx = cursor.getColumnIndex(Phone._ID);
                int nameIdx = cursor.getColumnIndex(Phone.DISPLAY_NAME);
                int phoneNumberIdx = cursor.getColumnIndex(Phone.NUMBER);
                int photoIdIdx = cursor.getColumnIndex(Phone.PHOTO_ID);
                cursor.moveToFirst();
                do {
                    String phoneNumber = cursor.getString(phoneNumberIdx);
                    numberList.add(phoneNumber);
                } while (cursor.moveToNext());  
            } catch (Exception e) {
                e.printStackTrace();
            } finally {
                if (cursor != null) {
                    cursor.close();
                }
            }
    }

Answer 3

   Uri personUri = ContentUris.withAppendedId(People.CONTENT_URI, personId);
   Uri phonesUri = Uri.withAppendedPath(personUri,                   People.Phones.CONTENT_DIRECTORY);
   String[] proj = new String[] {Phones._ID, Phones.TYPE, Phones.NUMBER, Phones.LABEL}
        Cursor cursor = contentResolver.query(phonesUri, proj, null, null, null);
    if(cursor != null && cursor.moveToFirst()){
    do{
    String number = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                    int type = phoneCursor.getInt(phoneCursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.TYPE));
                    switch (type) {

                        case ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE:
                        break;   
                    }
    }while(cursor.moveToNext());
    }

我怎样才能从Android手机书中获得所有手机号码？

3 个答案: