Question

我在$ a中有一个时隙数组：

10:00 am,11:00 am,12:00 pm,01:00 pm,02:00 pm,03:00 pm,04:00 pm

我想从数组中删除除am/pm的第一个实例以外的所有实例：

10:00 am,11:00,12:00 pm,01:00 pm,02:00,03:00, 04:00

str_replace()会全力以赴。 preg_replace会让我限制我取出的数量，但不会让我除外1.但是我需要为此编写自己的功能吗？是否有优雅的解决方案？

Answer 1

你可以试试这个，它只保留你想要的第一个上午/下午字符串：

select STUFF((Select ','+email_receiver from dbo.rms_emails where is_active =1 FOR XML PATH('')),1,1,'')

输出：

$timeSlots = array(
    "10:00 am",
    "11:00 am",
    "12:00 pm",
    "01:00 pm",
    "02:00 pm",
    "03:00 pm",
    "04:00 pm"
);

$foundAm = false;
$foundPm = false;

foreach( $timeSlots as $index => $timeSlot ) {
    if( strpos( $timeSlot, "am" ) !== false && $foundAm === false ) {
            $foundAm = true;
            continue;
    } else if( strpos( $timeSlot, "pm" ) !== false && $foundPm === false ) {
            $foundPm = true;
            continue;
    }

     $timeSlots[$index] = trim( str_replace( array( "am", "pm" ) , "", $timeSlot ) );
}

echo "<pre>";
var_dump( $timeSlots );

echo implode( ",", $timeSlots );

Answer 2

如果它的类似这样的数组可以工作，我想（只有当没有设置键或者你知道第一个键时）

$times = array('10:00 am','11:00 am','12:00 pm','01:00 pm','02:00 pm','03:00 pm','04:00 pm');
foreach($times as $key => $time){
    if($key != 0){
        $search = array(" am", " pm");
        $times[$key] = str_replace($search, "", $time);
    }
    //So if the key is 0 (The first element) continue, else remove the am/pm
}

删除所有am / pm但是数组中的第一个实例

2 个答案: