Jquery DatePicker不包含所有依赖项

时间:2015-09-22 08:35:12

标签: javascript jquery jquery-ui datepicker

我正在尝试设置Jquery UI datepicker,但它无效。我在这里制作了我的设置演示:https://jsfiddle.net/950g0oku/

输入字段是

<input id="id_dates-0-starts" class="datetime field_required hasDatepicker" type="text" name="dates-0-starts">

和javascript

$(".datetime").datepicker();

4 个答案:

答案 0 :(得分:1)

我刚删除了班级hasDatepicker,现在正在工作:

https://jsfiddle.net/950g0oku/3/

答案 1 :(得分:1)

为什么使用hasDatepicker课程?从输入中删除它,它的工作原理。请参阅the Fiddle

事实上,jQuery-ui也使用这个类名,所以当你使用它时,似乎存在冲突。

答案 2 :(得分:1)

您需要从字段中删除课程 WITH a AS ( SELECT round AS round ,Sum(non_slsc_qty) AS SC ,Sum(non_slst_qty) AS ST ,Sum(non_slot_qty) AS OTHERS FROM vhn_issue WHERE ( DATE BETWEEN '2015-08-01' AND '2015-08-31' ) AND dvn_cd = '15' AND phc_cd = '012' AND hsc_cd = '05' GROUP BY round ) ,b AS ( SELECT round AS round_up ,Sum(non_slsc_qty) AS SC_up ,Sum(non_slst_qty) AS ST_up ,Sum(non_slot_qty) AS OTHERS_up , FROM vhn_issue WHERE ( DATE BETWEEN '2015-04-01' AND '2015-08-31' ) AND dvn_cd = '15' AND phc_cd = '012' AND hsc_cd = '05' GROUP BY round ) SELECT coalesce(b.round_up, 0) round_up ,coalesce(a.sc, 0) sc ,coalesce(a.st, 0) st ,coalesce(a.others, 0) others ,coalesce(b.sc_up, 0) sc_up ,coalesce(b.st_up, 0) st_up ,coalesce(b.others_up, 0) others_up FROM a RIGHT JOIN b ON a.round = b.round_up

看看你的小提琴updated version(你的更新)。

jQuery使用这个类,似乎如果使用类hasDatepicker,日历的功能就不会显示任何内容。

希望它可以帮助

答案 3 :(得分:0)

不要使用hasDatepicker作为班级名称。 jquery datepicker使用此名称进行渲染。请参阅此jsfiddle