在oracle中解码，具有多个条件

Question

Select decode(a.Type,1,'ONE',2,'TWO',null ,'OTHER')|| 
       Decode (b.Active, 1 ,'Yes',0,'NO', null ,'NO'),
       count(*) 
from TypeTable a,
     Status b 
where a.id=b.id 
  and a.type in(12,3,34,45,66);

现在的问题是，

我想计算那些有记录的类型1和其他的人 喜欢

Column1        |  Column2 
---------------+----------
One            |   10
ONE                                        
Other that ONE |   20

Answer 1

我不确定你想要什么。也许你正在寻找类似于我的例子。

select decode(object_type,'SYNONYM','SYNONYM','OTHER THAN SYNONYM') column1, count(*) column2 from user_objects 
group by decode(object_type,'SYNONYM','SYNONYM','OTHER THAN SYNONYM');