Question

朋友们，关于Creating JSON structure from JSON results的问题，我怎样才能创建具有多个数组头的对象？

var array = [
    [{
    "label": "NewNetworkServiceProvider",
        "value": "NewNetworkServiceProvidered46c4ee-7ec1-45d6-9d13-94e301d2f890"
}, {
    "label": "PurchaseOrderNumber",
        "value": "PurchaseOrderNumber4be9f460-0c98-4038-910d-027565f83e1c"
}, {
    "label": "RawRecordType",
        "value": "RawRecordType2a774afb-0fd4-4fd4-a3c6-88041de5b1ad"
}],
[{
    "label": "NewNetworkServiceProvider",
        "value": "NewNetworkServiceProvidered46c4ee-7ec1-45d6-9d13-94e301d2f890"
}, {
    "label": "PurchaseOrderNumber",
        "value": "PurchaseOrderNumber4be9f460-0c98-4038-910d-027565f83e1c"
}, {
    "label": "RawRecordType",
        "value": "RawRecordType2a774afb-0fd4-4fd4-a3c6-88041de5m321"
}]
   ];

var obj = {
    header: {}
};
array.forEach(function (item) {
    item.forEach(function (data) {
        obj.header[data.label] = data.value;
    });
});

console.log(obj)

Answer 1

猜测我认为你想要这个：

array.forEach(function (item) {
    item.forEach(function (data) {
        obj.header[data.label] = obj.header[data.label] || [];
        obj.header[data.label].push(data.value);
    });
});

http://jsfiddle.net/867mb14s/1/

Answer 2

您的array不正确。如果你有不同的标签名称，你提供的JS代码就可以完美地运行，如果标签名称相同，那么最新的值将取代旧值。

所以，试试这段代码吧。它给出了所有标题名称。

var array = [
  [{
    "label": "0_NewNetworkServiceProvider",
    "value": "0_NewNetworkServiceProvidered46c4ee-7ec1-45d6-9d13-94e301d2f890"
  }, {
    "label": "0_PurchaseOrderNumber",
    "value": "0_PurchaseOrderNumber4be9f460-0c98-4038-910d-027565f83e1c"
  }, {
    "label": "0_RawRecordType",
    "value": "0_RawRecordType2a774afb-0fd4-4fd4-a3c6-88041de5b1ad"
  }],
  [{
    "label": "1_NewNetworkServiceProvider",
    "value": "1_NewNetworkServiceProvidered46c4ee-7ec1-45d6-9d13-94e301d2f890"
  }, {
    "label": "1_PurchaseOrderNumber",
    "value": "1_PurchaseOrderNumber4be9f460-0c98-4038-910d-027565f83e1c"
  }, {
    "label": "1_RawRecordType",
    "value": "1_RawRecordType2a774afb-0fd4-4fd4-a3c6-88041de5m321"
  }]
];

var obj = {
  header: {}
};
array.forEach(function(item) {
  item.forEach(function(data) {
    obj.header[data.label] = data.value;
  });
});

console.log(obj)

查看array数据的差异。

@Jaromanda X也是正确的，但他在每个标题内取出记录为数组。

从具有许多记录的JSON结果创建JSON结构

2 个答案: