Question

我是JS的新手，想知道将以下内容在JavaScript中转换为对象的最佳方法是什么？我想保留字符串化的键值对。

[
    "\"Matt Forte : 17",
    "C.J. Anderson : 16",
    "Jamaal Charles : 16",
    "Eddie Lacy : 15",
    "Andre Ellington : 14",
    "LeSean McCoy : 14",
    "Marshawn Lynch : 14Tre Mason : 13",
    "Latavius Murray : 13",
    "Rashad Jennings : 12",
    "Alfred Morris : 12",
    "Jonathan Stewart : 12",
    "Doug Martin : 12",
    "Chris Ivory : 12",
    "\""
]

我尝试了这个，但它不起作用！是否有任何内置组件可以为我做这样的事情？也许我应该将数据作为一个对象存储起来......

var players = [
    "\"Matt Forte : 17",
    "C.J. Anderson : 16",
    "Jamaal Charles : 16",
    "Eddie Lacy : 15",
    "Andre Ellington : 14",
    "LeSean McCoy : 14",
    "Marshawn Lynch : 14Tre Mason : 13",
    "Latavius Murray : 13",
    "Rashad Jennings : 12",
    "Alfred Morris : 12",
    "Jonathan Stewart : 12",
    "Doug Martin : 12",
    "Chris Ivory : 12",
    "\""
];

var obj = {};
for (var i = 0; i< players.length; i++) {
    var tuple = players[i].split(":");
    console.log(tuple);
    for(var key in obj){
        key = tuple[0];
        obj[key] = tuple[1];

    }
};

console.log(obj);

Answer 1

像这样：

function prestoChango(ary){
  var o = {};
  for(var i=0,l=ary.length; i<l; i++){
    var s = ary[i].split(/\s*\:\s*/);
    o[s[0]] = +s[1];
  }
  return o;
}
console.log(prestoChango(arrayOfStrings));

Answer 2

使用Array.prototype.map

var stringArray = [
  "\"Matt Forte : 17",
  "C.J. Anderson : 16",
  "Jamaal Charles : 16",
  "Eddie Lacy : 15",
  "Andre Ellington : 14",
  "LeSean McCoy : 14",
  "Marshawn Lynch : 14Tre Mason : 13",
  "Latavius Murray : 13",
  "Rashad Jennings : 12",
  "Alfred Morris : 12",
  "Jonathan Stewart : 12",
  "Doug Martin : 12",
  "Chris Ivory : 12",
  "\""
];

var objectArray = stringArray.map(function(string) {
  var splat = string.replace("\"", "").split(' : ');
  var obj = {};
  obj[splat[0]] = splat[1];
  return obj;
});

console.log(objectArray);

Answer 3

尝试使用RegExp拆分键和值：

var arr = [
  "\"Matt Forte : 17",
  "C.J. Anderson : 16",
  "Jamaal Charles : 16",
  "Eddie Lacy : 15",
  "Andre Ellington : 14",
  "LeSean McCoy : 14",
  "Marshawn Lynch : 14Tre Mason : 13",
  "Latavius Murray : 13",
  "Rashad Jennings : 12",
  "Alfred Morris : 12",
  "Jonathan Stewart : 12",
  "Doug Martin : 12",
  "Chris Ivory : 12",
  "\""
];
//re-build proper key-value pairs
arr = arr.join('').match(/([\w|\.\s]*\:\s\d*)/g);
var obj = {};
var l = arr.length;
var tmp;
var rgx = /\s?\:\s?/;
while (l--) {
  tmp = arr[l].split(rgx);
  obj[tmp[0]] = tmp[1];
}
document.write("<pre>");
document.write(JSON.stringify(arr));
document.write("<br/>");
document.write(JSON.stringify(obj, 0, 4));
document.write("</pre>");

Answer 4

使用map函数创建两个新数组，分别包含键和值。

创建一个空对象，然后遍历键或值数组。

var names = players.map(function(player) { return player.split(':')[0] }
var score = players.map(function(player) { return player.split(':')[1] }

var object = {}

for (var i = 0; i < names.length; i++) {
   object[names[i]] = score[i];
}

这是我的输出看起来像

{ 'Matt Forte': '17',
  'C.J. Anderson': '16',
  'Jamaal Charles': '16',
  'Eddie Lacy': '15'
...
}

Answer 5

不幸的是，使用split的所有发布的答案都会破坏数组的最后一项。这是一个稍微复杂的方法应该可以正常工作：

var object = {};
players.map(function(string) {
  string.replace(/(.+) : (\d+)/,function($0,$1,$2){object[$1]=$2;});
});

将字符串数组（其中每个字符串是键值对）转换为对象

5 个答案: