自定义ListView适配器中的StartActivity

时间:2015-09-21 22:39:07

标签: java android

我在我的自定义onClick中设置TextView到我的ListView来电。点击TextView后,我希望它能够打开Android的拨号屏幕。我将我的Activity的Context传递给了我的自定义适配器Java类,但每次点击TextView时,应用程序仍然会崩溃。以下代码由构造函数以及我的自定义适配器Java类中的最后几个方法组成:

    public CustomAdapter(Context c,ArrayList<String>n,ArrayList<String>nums, ArrayList<String>e){
           context = c;
           phoneNumbers = nums;
           names = n;
           emails = e;
           inflater = (LayoutInflater)context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
}

...

    public View getView(int position, View convertView, ViewGroup parent) {
    View view = convertView;

    if (view == null){
        view = inflater.inflate(R.layout.contacts_custom_row,null);
        TextView phone = (TextView)view.findViewById(R.id.customRowContactNumber);

        phone.setOnClickListener(this);
    }
    return view;
}

@Override
public void onClick(View v) {
    switch (v.getId()){
        case R.id.customRowContactNumber:{
            Intent i = new Intent(Intent.ACTION_DIAL);
            context.startActivity(i);//I passed the context to my constructor
            break;
        }
    }

}

请让我知道我做错了什么,谢谢。这是log cat错误:

09-21 17:48:49.451    2003-2003/com.markfeldman.mydoggydays E/AndroidRuntime﹕ FATAL EXCEPTION: main
Process: com.markf.dogdays, PID: 2003
android.util.AndroidRuntimeException: Calling startActivity() from outside of an Activity  context requires the FLAG_ACTIVITY_NEW_TASK flag. Is this really what you want?
        at android.app.ContextImpl.startActivity(ContextImpl.java:1238)
        at android.app.ContextImpl.startActivity(ContextImpl.java:1225)
        at android.content.ContextWrapper.startActivity(ContextWrapper.java:323)
        at com.markfeldman.mydoggydays.CustomAdapter.onClick(CustomAdapter.java:71)
        at android.view.View.performClick(View.java:4780)
        at android.view.View$PerformClick.run(View.java:19866)
        at android.os.Handler.handleCallback(Handler.java:739)
        at android.os.Handler.dispatchMessage(Handler.java:95)
        at android.os.Looper.loop(Looper.java:135)
        at android.app.ActivityThread.main(ActivityThread.java:5257)
        at java.lang.reflect.Method.invoke(Native Method)
        at java.lang.reflect.Method.invoke(Method.java:372)
        at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:903)
        at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:698)

2 个答案:

答案 0 :(得分:1)

如果你确定这里是你想要开始活动的地方,你可以添加

Intent i = new Intent(Intent.ACTION_DIAL);
i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);

然后按原样启动它,

context.startActivity(i);

看起来你传递的上下文不是Activity的上下文,这就是为什么它会给你警告。如果您确定,可以通过更改类声明来执行@fixmycode建议的内容。

答案 1 :(得分:0)

在你的班级声明中:

public CustomAdapter(Activity activity, ...){
    Activity myActivity = activity;
    ...
}

在你的onClick方法中:

myActivity.startActivity(...);