Question

我想创建一个名为WORKER的表，他建造的Square Meteres总数以及他支付的总费用。

我有2张桌子

tbl_orden和tbl_costos

obrero是tbl_costos中的外键

这是我尝试的查询：

SELECT a.obrero AS MAESTRO, ROUND(SUM(metros_c),2) AS METROS, SUM(b.costo_semanal)
FROM tbl_orden as a, tbl_costos as b GROUP BY a.obrero

我尝试上面的查询，但我没有得到正确的结果。 metros_c的SUM不是costo_semanal的总和

tbl_order

id（int）主键
name_obra（varchar）
num_fab（int）
日期（日期）
type（varchar）
obrero（varchar）
metros_c（float）
评论（varchar）

tbl_costos：

id（int）主键
costo_semanal（float）
obrero（来自tbl_order的外键）
fechai（约会）
fechaf（日期）

我想要这个查询结果：

 SELECT obrero AS Maestro, ROUND(SUM(metros_c),2) AS Metros_Cuadrados, ROUND(SUM(metros_c)/MONTH(CURDATE()),2) as Promedio_Mensual, ROUND(SUM(metros_c)/WEEK(CURDATE()),2) as Promedio_Semanal FROM `tbl_orden`
          WHERE dated BETWEEN '01/01/2015' AND '01/01/2016' GROUP BY obrero ORDER BY metros_c asc

并且此查询会生成上表的其他列：

SELECT SUM(costo_semanal) from tbl_costos GROUP BY obrero

第一个查询我得到4列，第二个得到1.我希望得到一个包含5列的结果表

Answer 1

您可以将每个放入内联视图，然后将它们连接起来执行此操作：

select x.*,
       y.sum_costo_semanal
  from (select obrero as maestro,
               round(sum(metros_c), 2) as metros_cuadrados,
               round(sum(metros_c) / month(curdate()), 2) as promedio_mensual,
               round(sum(metros_c) / week(curdate()), 2) as promedio_semanal
          from tbl_orden
         where dated between '01/01/2015' and '01/01/2016'
         group by obrero) x
  join (select obrero,
               sum(costo_semanal) as sum_costo_semanal
          from tbl_costos
         group by obrero) y
    on x.obrero = y.obrero

使用不同的查询mysql创建表

1 个答案: