我正在制作自己的c shell。 shell具有显示过去命令的历史记录功能。我已经走得那么远,但我无法重新运行旧命令。我试图在用户输入rr时重新运行最后一个命令。 当rr = args [0]时,问题在主函数中标记。
这是我的代码:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#define MAX_LINE 80 /* 80 chars per line, per command, should be enough. */
#define HIST_SIZE 12
int place=0;
char cmd[MAX_LINE+1]; //used to keep copy of inBuffer to put in *hist
/** The setup() routine reads in the next command line string storing it in the input buffer.
The line is separated into distinct tokens using whitespace as delimiters. Setup also
modifies the args parameter so that it holds points to the null-terminated strings which
are the tokens in the most recent user command line as well as a NULL pointer, indicating the
end of the argument list, which comes after the string pointers that have been assigned to
args. ***/
void setup(char inputBuffer[], char *args[],int *background){
int length, /* # characters in the command line */
start, /* Beginning of next command parameter */
i, /* Index for inputBuffer arrray */
j; /* Where to place the next parameter into args[] */
/* Read what the user enters */
length = read(STDIN_FILENO, inputBuffer, MAX_LINE);
strcpy(cmd,inputBuffer);
start = -1;
j = 0;
if (length == 0)
exit(0); /* Cntrl-d was entered, end of user command stream */
if (length < 0){
perror("error reading command");
exit(-1); /* Terminate with error code of -1 */
}
/* Examine every character in the input buffer */
for (i = 0; i < length; i++) {
switch (inputBuffer[i]){
case ' ':
case '\t' : /* Argument separators */
if(start != -1){
args[j] = &inputBuffer[start]; /* Set up pointer */
j++;
}
inputBuffer[i] = '\0'; /* Add a null char; make a C string */
start = -1;
break;
case '\n': /* Final char examined */
if (start != -1){
args[j] = &inputBuffer[start];
j++;
}
inputBuffer[i] = '\0';
args[j] = NULL; /* No more arguments to this command */
break;
case '&':
*background = 1;
inputBuffer[i] = '\0';
break;
default : /* Some other character */
if (start == -1)
start = i;
}
}
args[j] = NULL; /* Just in case the input line was > 80 */
}
int displayHistory(char *hist[], int place){
int i=place;
int hist_num=1;
do{
if(hist[i]){
printf("%d %s", hist_num, hist[i]);
hist_num++;
}
i=(i+1)%HIST_SIZE;
} while(i != place);
return 0;
}
int main(void){
char inputBuffer[MAX_LINE]; /* Input buffer to hold the command entered */
char *args[MAX_LINE/2+1];/* Command line arguments */
int background; /* Equals 1 if a command is followed by '&', else 0 */
char *hist[HIST_SIZE];
int i=0;
for(i=0; i<HIST_SIZE; i++){
hist[i]=NULL;
}
while (1){ /* Program terminates normally inside setup */
background = 0;
printf("COMMAND--> "); /* Shell prompt */
fflush(0);
setup(inputBuffer, args, &background); /* Get next command */
if(strcmp(args[0],"rr")==0){
//rr does not go into *hist
}
else{
cmd[strlen(cmd)]='\0';
free(hist[place]);
hist[place]=strdup(cmd);
place=(place+1)%HIST_SIZE;
}
/* Fill in the code for these steps:
(1) Fork a child process using fork(),
(2) The child process will invoke execvp(),
(3) If background == 0, the parent will wait,
o/w returns to the setup() function. */
pid_t pid=fork();
int status;
if(pid<0){ //error forking
fprintf(stderr, "Fork Failed");
exit(-1);
}
else if(pid==0){ //child process
if(strcmp(inputBuffer,"h")==0){
displayHistory(hist,place);
}
else if(strcmp(args[0],"rr")==0){
printf("%s",hist[place-1]); //this is here to show that hist[place-1] does have the last command
execvp(hist[place-1], args); //PROBLEM HERE. why doesn't the hist[place-1]get executed?
}
else{
if(execvp(inputBuffer, args)<0){
printf("Invalid Command\n");
}
}
}
else{ //parent process
if(background==0){ //wait
waitpid(pid, &status, 0);
}
}
memset(inputBuffer,0,sizeof(inputBuffer)); //this is done so garbage chars from old input does not show up later when history is displayed
memset(cmd, 0, sizeof(cmd));
}
}
解释为什么不执行旧命令会很好。实际上运行命令的方法很棒。
答案 0 :(得分:1)
要推进循环缓冲区索引,请正确使用
place = (place + 1) % HIST_SIZE
但是你用
错误地退后一步hist[place - 1]
这应该是
hist [ (place + HIST_SIZE - 1) % HIST_SIZE ]