Question

在给定的函数中，我传递的数据是json格式，如下所示

[{"Date":"2014-12-12 18:52:10","TTC":"0"},{"Date":"2014-12-12 18:52:10","TTC":"0"},{"Date":"2014-12-12 18:53:10","TTC":"0"},{"Date":"2014-12-12 18:53:10","TTC":"0"},{"Date":"2014-12-12 19:02:11","TTC":"0"}]

JSON数组太长了，我想将Date存入日期数组，将TTC存储到ttc中，请帮助解析。

 function drawChart(data){

            console.log(data);
            var date = [];
            var ttc = [];

            for(var i=0; i<data.length; i++){

                date.push(data[i]['Date']);
                console.log(date);
                ttc.push(parseInt(data[i]["TTC"]));
                //console.log(ttc);
            }
}

Answer 1

以这种方式尝试：

var data = [{
  "Date": "2014-12-12 18:52:10",
  "TTC": "0"
}, {
  "Date": "2014-12-12 18:52:10",
  "TTC": "0"
}, {
  "Date": "2014-12-12 18:53:10",
  "TTC": "0"
}, {
  "Date": "2014-12-12 18:53:10",
  "TTC": "0"
}, {
  "Date": "2014-12-12 19:02:11",
  "TTC": "0"
}];

function drawChart(data) {
  var date = [];
  var ttc = [];
  for (var i = 0; i < data.length; i++) {
    date.push(data[i]['Date']);
    ttc.push(parseInt(data[i]["TTC"]));
  }
  return {
    date: date,
    ttc: ttc
  };
}
document.body.innerHTML = JSON.stringify(drawChart(data));

您需要返回一个包含数组的对象

Answer 2

为了像对象一样访问它，你必须像这样解析它：

obj = JSON.parse(data);

如何将JSON数组解码为两个varibale？

2 个答案: