Question

由于数据库查询，我有一个数组。行包括两个维度和一些指标。度量标准必须按维度组进行求和。

以下是表视图中的示例原始数据数组：

这是确切的数组：

array(13) {
  [0]=>
  array(6) {
    ["source_name"]=>
    string(8) "A"
    ["week"]=>
    string(2) "10"
    ["picks"]=>
    int(1)
    ["won"]=>
    int(0)
    ["lost"]=>
    int(1)
    ["draw"]=>
    int(0)
  }
  [1]=>
  array(6) {
    ["source_name"]=>
    string(8) "A"
    ["week"]=>
    string(2) "10"
    ["picks"]=>
    int(1)
    ["won"]=>
    int(1)
    ["lost"]=>
    int(0)
    ["draw"]=>
    int(0)
  }
  [2]=>
  array(6) {
    ["source_name"]=>
    string(8) "A"
    ["week"]=>
    string(2) "11"
    ["picks"]=>
    int(1)
    ["won"]=>
    int(1)
    ["lost"]=>
    int(0)
    ["draw"]=>
    int(0)
  }
  [3]=>
  array(6) {
    ["source_name"]=>
    string(8) "A"
    ["week"]=>
    string(2) "11"
    ["picks"]=>
    int(1)
    ["won"]=>
    int(1)
    ["lost"]=>
    int(0)
    ["draw"]=>
    int(0)
  }
  [4]=>
  array(6) {
    ["source_name"]=>
    string(8) "A"
    ["week"]=>
    string(2) "11"
    ["picks"]=>
    int(1)
    ["won"]=>
    int(0)
    ["lost"]=>
    int(1)
    ["draw"]=>
    int(0)
  }
  [5]=>
  array(6) {
    ["source_name"]=>
    string(8) "A"
    ["week"]=>
    string(2) "11"
    ["picks"]=>
    int(1)
    ["won"]=>
    int(0)
    ["lost"]=>
    int(1)
    ["draw"]=>
    int(0)
  }
  [6]=>
  array(6) {
    ["source_name"]=>
    string(8) "A"
    ["week"]=>
    string(2) "11"
    ["picks"]=>
    int(1)
    ["won"]=>
    int(1)
    ["lost"]=>
    int(0)
    ["draw"]=>
    int(0)
  }
  [7]=>
  array(6) {
    ["source_name"]=>
    string(7) "B"
    ["week"]=>
    string(2) "10"
    ["picks"]=>
    int(1)
    ["won"]=>
    int(0)
    ["lost"]=>
    int(1)
    ["draw"]=>
    int(0)
  }
  [8]=>
  array(6) {
    ["source_name"]=>
    string(7) "B"
    ["week"]=>
    string(2) "10"
    ["picks"]=>
    int(1)
    ["won"]=>
    int(1)
    ["lost"]=>
    int(0)
    ["draw"]=>
    int(0)
  }
  [9]=>
  array(6) {
    ["source_name"]=>
    string(7) "B"
    ["week"]=>
    string(2) "11"
    ["picks"]=>
    int(1)
    ["won"]=>
    int(0)
    ["lost"]=>
    int(1)
    ["draw"]=>
    int(0)
  }
  [10]=>
  array(6) {
    ["source_name"]=>
    string(7) "B"
    ["week"]=>
    string(2) "11"
    ["picks"]=>
    int(1)
    ["won"]=>
    int(1)
    ["lost"]=>
    int(0)
    ["draw"]=>
    int(0)
  }
  [11]=>
  array(6) {
    ["source_name"]=>
    string(9) "C"
    ["week"]=>
    string(2) "11"
    ["picks"]=>
    int(1)
    ["won"]=>
    int(1)
    ["lost"]=>
    int(0)
    ["draw"]=>
    int(0)
  }
  [12]=>
  array(6) {
    ["source_name"]=>
    string(9) "C"
    ["week"]=>
    string(2) "11"
    ["picks"]=>
    int(1)
    ["won"]=>
    int(1)
    ["lost"]=>
    int(0)
    ["draw"]=>
    int(0)
  }
}

这是我期望得到的输出：

获得该输出的最佳方法是什么？

感谢。

Answer 1

你可以像在

一样在这里做foreach

$result = [];
foreach($data as $key => $value){
    $hash = $value['source_name'] ."_". $value['week'];

    if(isset($result[$hash])){
         $result[$hash]['picks'] += $value['picks'];
         $result[$hash]['won'] += $value['won'];
         $result[$hash]['lost'] += $value['lost'];
         $result[$hash]['draw'] += $value['draw'];
    }else{
         $result[$hash] = $value;
    }
}
print_r(array_values($result));

Answer 2

您提到此数组是数据库查询的结果。因此，您不应该像这样迭代结果，您应该关注如何从数据库中获取这些结果，因为SQL可以为您提供更好的性能所需的所有数学。

为了向您展示，假设您的数据库表名为my_table，并且包含您在上面发布的所有信息：（source_name，week，picks，{{1 }}，won，lost）：

draw

如果您运行以下SQL查询，您将获得所需的结果，而无需担心以后的迭代或循环。

+-------------+------+-------+-----+------+------+
| source_name | week | picks | won | lost | draw |
+-------------+------+-------+-----+------+------+
| A           | 10   | 1     | 0   | 1    | 0    |
+-------------+------+-------+-----+------+------+
| A           | 10   | 1     | 1   | 0    | 0    |
+-------------+------+-------+-----+------+------+
| A           | 11   | 1     | 1   | 0    | 0    |
+-------------+------+-------+-----+------+------+
| A           | 11   | 1     | 1   | 0    | 0    |
+-------------+------+-------+-----+------+------+
| A           | 11   | 1     | 0   | 1    | 0    |
+-------------+------+-------+-----+------+------+
| A           | 11   | 1     | 0   | 1    | 0    |
+-------------+------+-------+-----+------+------+
| A           | 11   | 1     | 1   | 0    | 0    |
+-------------+------+-------+-----+------+------+
| B           | 10   | 1     | 0   | 1    | 0    |
+-------------+------+-------+-----+------+------+
| B           | 10   | 1     | 1   | 0    | 0    |
+-------------+------+-------+-----+------+------+
| B           | 11   | 1     | 0   | 1    | 0    |
+-------------+------+-------+-----+------+------+
| B           | 11   | 1     | 1   | 0    | 0    |
+-------------+------+-------+-----+------+------+
| C           | 11   | 1     | 1   | 0    | 0    |
+-------------+------+-------+-----+------+------+
| C           | 11   | 1     | 1   | 0    | 0    |
+-------------+------+-------+-----+------+------+

结果：

SELECT source_name, week, sum(picks), sum(won), sum(lost), sum(draw)
FROM my_table 
GROUP BY source_name, week 
ORDER BY source_name

请查看 SQL FIDDLE ，以帮助您了解它。

PHP从数据库结果中分组具有多维的数组

2 个答案: