Question

我有一张桌子：

                                    Table "public.activity"

   Column   |            Type             |           Modifiers                       
------------+-----------------------------+-------------------------------------------------------
 id         | integer                     | not null default nextval('activity_id_seq'::regclass)
 scheduleid | integer                     | 
 name       | text                        | 
 duedate    | timestamp without time zone | 
Indexes:
    "activity_pkey" PRIMARY KEY, btree (id)

使用以下数据：

 id | scheduleid |   name   |          duedate           
----+------------+----------+----------------------------
  1 |          1 | ACT1     | 2015-09-21 13:34:53.738449
  2 |          1 | ACT1     | 2015-09-20 13:35:02.770369
  3 |          1 | ACT1     | 2015-09-19 13:35:07.650204
  4 |          1 | ACT1     | 2015-09-18 13:35:11.930225
  5 |          1 | ACT1.0.0 | 2015-09-17 13:35:48.033791
  6 |          1 | ACT1.0.0 | 2015-09-16 13:35:51.55382
  7 |          2 | ACT2.0.0 | 2015-09-21 13:36:56.42534
  8 |          2 | ACT2.0.0 | 2015-09-28 13:37:21.065071
  9 |          2 | ACT2.0.0 | 2015-10-05 13:37:26.753227
 10 |          2 | ACT2.0.0 | 2015-10-12 13:37:30.656846
 11 |          2 | ACT2.0.0 | 2015-10-19 13:37:34.54473
 12 |          2 | ACT2.0.0 | 2015-10-26 13:37:38.192843
(12 rows)

对于每个scheduleId，我们已创建活动。

我需要显示每个时间表的最新独特活动以及其下的活动数量。

使用Postgres窗口函数进行查询后，就可以完成它的工作。

WITH TOP_ACTIVITIES AS (
    SELECT DISTINCT ON (scheduleid, name)
    id, scheduleid, name, duedate,
    count(*) over(partition by scheduleid, name) as clubbedcount
    from activity ORDER BY scheduleid, name, duedate desc
)
select * from TOP_ACTIVITIES;

结果如下：

id | scheduleid |   name   |          duedate           | clubbedcount 
----+------------+----------+----------------------------+--------------
  1 |          1 | ACT1     | 2015-09-21 13:34:53.738449 |            4
  5 |          1 | ACT1.0.0 | 2015-09-17 13:35:48.033791 |            2
 12 |          2 | ACT2.0.0 | 2015-10-26 13:37:38.192843 |            6

到目前为止一切顺利：P

现在一个小小的转折，我们需要按照他们的rangeTag对活动进行分组

Eg: Todays date being 21-Sep-2015,
activities with duedate <= now() --> club under TODAY tag
activities with duedate <= now() + 7 days --> club under THIS WEEK tag
activities with duedate <= now() + 1 month --> club under THIS MONTH tag
ELSE --> club under FUTURE tag

因此我们需要 1.由rangeTag，scheduleid和name定义的每个分区的顶层活动 2.活动计数，将每个分区整理为最高活动。

将我的查询略微修改为：

WITH TOP_ACTIVITIES AS (
     SELECT DISTINCT ON (range, scheduleid, name)
     id, scheduleid, name, duedate,

     CASE WHEN duedate < now() THEN 'TODAY'
          WHEN duedate < now() + interval '7 days' THEN 'THIS WEEK'
          WHEN duedate < now() + interval '1 month' THEN 'THIS MONTH'
          ELSE 'FUTURE' 
     END AS range,

     count(*) over(partition by scheduleid, name)


     from activity ORDER BY range, scheduleid, name,duedate desc
)
select * from TOP_ACTIVITIES ORDER BY scheduleid;

给了我NEAR想要的结果，除了count：P

 id | scheduleid |   name   |          duedate           |   range    | count 
----+------------+----------+----------------------------+------------+-------
  1 |          1 | ACT1     | 2015-09-21 13:34:53.738449 | TODAY      |     4
  5 |          1 | ACT1.0.0 | 2015-09-17 13:35:48.033791 | TODAY      |     2
 12 |          2 | ACT2.0.0 | 2015-10-26 13:37:38.192843 | FUTURE     |     6
 11 |          2 | ACT2.0.0 | 2015-10-19 13:37:34.54473  | THIS MONTH |     6
  8 |          2 | ACT2.0.0 | 2015-09-28 13:37:21.065071 | THIS WEEK  |     6
  7 |          2 | ACT2.0.0 | 2015-09-21 13:36:56.42534  | TODAY      |     6

我也需要将数量划分为“范围”。

但是，替换

count(*) over(partition by scheduleid, name)

与

count(*) over(partition by range, scheduleid, name)

不起作用。

错误是

错误：列“范围”不存在
第9行：count（*）over（按范围划分，scheduleid，name）

Answer 1

将count()（和DISTINCT ON）移至新查询：

WITH top_activities AS (
    SELECT 
        id, scheduleid, name, duedate,
        CASE WHEN duedate < now() THEN 'TODAY'
            WHEN duedate < now() + interval '7 days' THEN 'THIS WEEK'
            WHEN duedate < now() + interval '1 month' THEN 'THIS MONTH'
            ELSE 'FUTURE'  
        END AS range
    FROM activity ORDER BY range, scheduleid, name,duedate desc
    ),
top_activities_with_count as (  
    SELECT DISTINCT ON (range, scheduleid, name)
        *, count(*) over(partition by range, scheduleid, name)
    FROM top_activities
    )
SELECT * FROM top_activities_with_count ORDER BY scheduleid;

PostgreSQL：使用列别名的窗口函数

1 个答案: