我有一个问题:
我想使用UNION将两个SQL查询连接到一个查询中以避免重复,但我需要知道数据是来自fisrt select查询还是来自第二个选择查询。
示例数据:
A TABLE B TABLE
-----------------------------------------------------------------------------
01 JOHN 01 JOHN
02 JUAN 02 PETER
03 MARTIN 03 MARTIN
我有这样的事情:
Select A.code,A.name from A where some conditions
unión
Select B.code,B.name from B where diferent conditions
结果表
01 JOHN
02 JUAN
02 PETER
03 MARTIN
这工作正常,但现在如果我想知道数据是来自第一个查询还是来自第二个我认为是这样的:
Select A.code,A.name, 'A' from A where some conditions
unión
Select B.code,B.name, 'B' from B where diferent conditions
结果表
01 JOHN 'A'
01 JOHN 'B'
02 JUAN 'A'
02 PETER 'B'
03 MARTIN 'A'
03 MARTIN 'B'
但是不要避免“重复”,因为'A'与'B'不同,所以问题是,我可以做一些事情,以便他们不将'A'与'B'进行比较吗?获得预期结果的另一种方法是什么?
编辑:
预期结果
01 JOHN 'A'
02 JUAN 'A'
02 PETER 'B'
03 MARTIN 'A'
答案 0 :(得分:3)
这是另一种方法:
SELECT code, name, MIN(SourceTable) AS SourceTable
FROM (
SELECT code, name, 'A' AS SourceTable
FROM A
UNION
SELECT code, name, 'B' AS SourceTable
FROM B) t
GROUP BY code, name
ORDER BY code
或者也许:
SELECT code, name, SourceTable
FROM (
SELECT code, name, SourceTable,
ROW_NUMBER() OVER (PARTITION BY code, name
ORDER BY SourceTable) AS rn
FROM (
SELECT code, name, 'A' AS SourceTable
FROM A
UNION ALL
SELECT code, name, 'B' AS SourceTable
FROM B) t) AS x
WHERE x.rn = 1
答案 1 :(得分:2)
Select A.code, A.name, 'A' from A where some conditions
union
Select B.code, B.name, 'B' from B
where different conditions
and not exists (select 1 from A
where some conditions
and A.code = B.code
and A.name = B.name)
像以前一样执行UNION
,但不要返回已从A select返回的B行。
答案 2 :(得分:1)
你可以试试这个:
Select A.code, A.name, 'A' col_name from A where some conditions
UNION ALL
Select B.code, B.name, 'B' from B where different conditions
Union将删除重复项,而Union All则不会。
修改强>
SELECT *
FROM
(
SELECT DISTINCT A.code, A.name From A WHERE some conditions
UNION
SELECT DISTINCT B.code, B.name From B WHERE different conditions
) t