Question

我正在客户端浏览器中显示一个消息框。它工作正常，但当弹出此警告消息框时，我看到后面有一个空白页面。但我希望用户始终看到他的浏览页面，然后弹出此消息框。这是我的代码如果（$ _ POST [＆＃39;提交＆＃39;] ==＆＃34;保存＆＃34） {

  $language=$_POST['pbx_lan'];

  if($language!="")
  {

  $query="update `account_detail` set `prompt_language`= '$language' WHERE `org_id`='".$_SESSION['account_id']."'";
  $result = $mysqli->query($query) or die($mysqli->error);


  $_SESSION['check_update'] = "1";
  // setcookie("msg","Language Successfully Updated",time()+5,"/");

  echo '<script>
  confirm("You have selected '.$language.'");
  window.location = "'.SITE_URL.'index.php?view=pbx_prompts."
  </script>';

  // header("location:".SITE_URL."index.php?view=view_service");

  }

  else
  {
  setcookie("err","No Language Selected.Please Select Language",time()+5,"/");
  header("location:".SITE_URL."index.php?view=view_service");
  }

  }`

Answer 1

当调用confirm()时，页面停止加载。当您在页面末尾添加confirm()时，页面会在confirm()显示之前加载

<body>
    TEST123
    <script>
        confirm('test');
    </script>
</body>

而不是

<body>
    <script>
        confirm('test');
    </script>
    TEST123
</body>

对于您的代码，这意味着

 echo '<script>
  confirm("You have selected '.$language.'");
  window.location = "'.SITE_URL.'index.php?view=pbx_prompts."
  </script>';

必须移到body标记的底部同时复制所需的if语句，以便仅在需要时执行代码。

body标记底部的完整代码应该是这样的：

if (!empty($language) && $_POST['submit'] == "Save") {
      echo '<script>
         confirm("You have selected '.$language.'");
         window.location = "'.SITE_URL.'index.php?view=pbx_prompts."
      </script>';
}

警报消息框显示

1 个答案: