Question

看起来简单（也许）但我需要将函数中的接收变量传递给另一个函数。这是我的代码：

PD：我使用的是Laravel Eloquent的范围

class myParentModel extends Model {

    public function scopeMyScope($query, $VAR_I_WANT_TO_PASS=[]) {

        return $query->with('model'])->whereHas('model', function($q, $VAR_I_WANT_TO_PASS=[]) {

            $q->where('colum1',$VAR_I_WANT_TO_PASS[0])->where('colum2',$VAR_I_WANT_TO_PASS[1])->where('colum3',$VAR_I_WANT_TO_PASS[2]);

        })->take(10);

    }
}

我想这样做：

$result = myParentModel::myScope([3,1,6])->get();

Answer 1

我使用use解决了这个问题：

class myParentModel extends Model {

    public function scopeMyScope($query, $VAR_I_WANT_TO_PASS) {

        return $query->with('model'])->whereHas('model', function($q) use ($VAR_I_WANT_TO_PASS) {

            $q->where('colum1',$VAR_I_WANT_TO_PASS[0])->where('colum2',$VAR_I_WANT_TO_PASS[1])->where('colum3',$VAR_I_WANT_TO_PASS[2]);

        })->take(10);

    }
}

PHP：将变量传递给函数

1 个答案: