Question

查询下面返回正确结果如果没有添加两个日期之间的where子句，否则它返回零，这是我创建的hibernate查询的sql等价物。在我的数据库日期保存为例如： - 2014年2月12日任何人都可以给我一个解决方案如何在两个给定日期之间获取结果。

select distinct count(customerjob0_.JOB_NUMBER) as col_0_0_ from JOB_CUSTOMER customerjob0_
left outer join SERVICE_LOCATION serviceloc1_ on customerjob0_.SERVICE_LOCATION_CODE=serviceloc1_.SERVICE_LOCATION_CODE 
left outer join JOB_CONTRACTS jobcontrac2_ on customerjob0_.JOB_NUMBER=jobcontrac2_.JOB_NUMBER 
left outer joinS CONTACTS contact3_ on jobcontrac2_.CONTACT_ID=contact3_.CONTACT_ID 
left outer join CUSTOMERS customer4_ on jobcontrac2_.CUST_CODE=customer4_.CUST_CODE 
left outer join CONTRACTS contract5_ on jobcontrac2_.CONTRACT_CODE=contract5_.CONTRACT_CODE 
left outer join JOB_CONTRACT_INVOICE jobcontrac6_ on jobcontrac2_.JOB_CONTRACT_ID=jobcontrac6_.JOB_CONTRACT_ID 
where to_char(customerjob0_.BU_NAME)='xYX01'
and (to_char(customerjob0_.BRANCH_NAME) like 'UX902')
and (to_char(customerjob0_.JOB_STATUS) in (2390 , 23400))
and to_char(customerjob0_.JOB_TYPE)='TEST' 
and (to_char(customerjob0_.JOB_FINISH_DATE) between '18-Sep-2008' and '18-Sep-2015');

Answer 1

select distinct count(customerjob0_.JOB_NUMBER) as col_0_0_ from JOB_CUSTOMER customerjob0_
left outer join SERVICE_LOCATION serviceloc1_ on customerjob0_.SERVICE_LOCATION_CODE=serviceloc1_.SERVICE_LOCATION_CODE 
left outer join JOB_CONTRACTS jobcontrac2_ on customerjob0_.JOB_NUMBER=jobcontrac2_.JOB_NUMBER 
left outer joinS CONTACTS contact3_ on jobcontrac2_.CONTACT_ID=contact3_.CONTACT_ID 
left outer join CUSTOMERS customer4_ on jobcontrac2_.CUST_CODE=customer4_.CUST_CODE 
left outer join CONTRACTS contract5_ on jobcontrac2_.CONTRACT_CODE=contract5_.CONTRACT_CODE 
left outer join JOB_CONTRACT_INVOICE jobcontrac6_ on jobcontrac2_.JOB_CONTRACT_ID=jobcontrac6_.JOB_CONTRACT_ID 
where to_char(customerjob0_.BU_NAME)='xYX01'
and (to_char(customerjob0_.BRANCH_NAME) like 'UX902')
and (to_char(customerjob0_.JOB_STATUS) in (2390 , 23400))
and to_char(customerjob0_.JOB_TYPE)='TEST' 
and customerjob0_.JOB_FINISH_DATE between '18-Sep-2008' and '18-Sep-2015';

实际上我从where子句中删除了to_char的日期并且它起作用了

在将日期条件添加到where子句时查询不给出结果

1 个答案: