我有一个gps设备,每隔10秒发送一次数据。我正在MySql数据库中保存数据(lat,lng)。我正在从DB中检索数据并使用xmlHttpRequest()将标记放在那些lat lng上。我也在10秒内使用setInterval()到xmlHttpRequest。标记正在精细添加,但刷新whol网站后添加新标记,而不是在xmlhttpreq上10秒后添加。
我也有两个问题 -
我的xmlHttpRequest()在10秒后刷新并获得get_data.php文件,正如我从网络,XHR看到的那样,但它没有在地图上添加新标记,但是10秒后请求xmlHttp 。我怎样才能更新标记?
根据数据库数据添加标记,但我不想要很多标记,我只想要一个标记,每10秒更新一次位置。因此,将删除先前的标记,并添加新标记。我怎样才能做到这一点?以下是我的代码 -
的index.html
<!DOCTYPE HTML>
<html>
<head>
<style type="text/css">
#map-canvas{
height: 500px;
}
</style>
<title> Google Map Test</title>
<script type="text/javascript" src="https://maps.googleapis.com/maps/api/js?sensor=false"></script>
<script type="text/javascript">
var map;
//var geocoder = new google.maps.Geocoder();
//var infowindow = new google.maps.InfoWindow();
function makeRequest(url, callback) {
var request;
if (window.XMLHttpRequest) {
request = new XMLHttpRequest(); // IE7+, Firefox, Chrome, Opera, Safari
} else {
request = new ActiveXObject("Microsoft.XMLHTTP"); // IE6, IE5
}
request.onreadystatechange = function() {
console.log(request)
if (request.readyState == 4 && request.status == 200) {
callback(request);
}
}
request.open("GET", url, true);
request.send();
console.log(request)
}
function initialise(){
var mapOptions = {
center: new google.maps.LatLng(23.7000, 90.3667),
zoom: 8,
mapTypeId: google.maps.MapTypeId.ROADMAP
};
map = new google.maps.Map(document.getElementById("map-canvas"),mapOptions);
makeRequest('get_data.php', function(data) {
var data = JSON.parse(data.responseText);
for (var i = 0; i < data.length; i++) {
displayLocation(data[i]);
}
});
// var myLatLng = {lat: 23.7000, lng: 90.3667};
// var marker = new google.maps.Marker({
// map: map,
// position: myLatLng,
// title: 'test!'
// });
}
setInterval("makeRequest('get_data.php')",10000);
function displayLocation(location) {
//var content = '<div class="infoWindow"><strong>' + location.lat +'</strong>'
// + '<br/>' + location.lon + '</div>';
console.log(location.lat)
// location = JSON.parse(location)
var position = new google.maps.LatLng(parseFloat(location.lat), parseFloat(location.lng));
var marker = new google.maps.Marker({
map: map,
position: position,
title: 'test!'
});
// google.maps.event.addListener(marker, 'click', function() {
// infoWindow.setContent(content);
// infoWindow.open(map,marker);
// });
}
</script>
</head>
<body>
<div id="map-canvas"></div>
<script type="text/javascript">
initialise();
</script>
</body>
</html>
get_data.php
$connection = mysqli_connect("localhost", "root", "123", "gpsdata") or die("Error " . mysqli_error($connection));
$sql = "select * from locations";
$result = mysqli_query($connection, $sql) or die("Error in Selecting " . mysqli_error($connection));
$emparray = [];
while($row = mysqli_fetch_assoc($result)) {
$emparray[] = $row;
}
echo json_encode($emparray);
mysqli_close($connection);
答案 0 :(得分:1)
您有两个选项,都涉及在displayLocation
函数之外保留对标记的引用:
var marker;
function displayLocation(location) {
console.log(location.lat)
var position = new google.maps.LatLng(parseFloat(location.lat), parseFloat(location.lng));
if (marker && marker.setPosition) {
// if the marker already exists, move it (set its position)
marker.setPosition(location);
} else {
// create a new marker, keeping a reference
marker = new google.maps.Marker({
map: map,
position: position,
title: 'test!'
});
}
}
var marker;
function displayLocation(location) {
console.log(location.lat)
var position = new google.maps.LatLng(parseFloat(location.lat), parseFloat(location.lng));
if (marker && marker.setMap) {
// if the marker already exists, remove it from the map
marker.setMap(null);
}
// create a new marker, keeping a reference
marker = new google.maps.Marker({
map: map,
position: position,
title: 'test!'
});
}
答案 1 :(得分:0)
你应该做
map.addMarker(new MarkerOptions()
.position(new LatLng(parseFloat(location.lat), parseFloat(location.lng)))
.title("test!"));
在displayLocation函数
中