Question

我尝试使用Python 3进行测验。测验随机生成两个单独的数字和运算符。但是当我试图让用户输入他们的答案时，这会显示在shell中：

<class 'int'>

我不确定自己需要做什么。即使我输入正确答案，它也总是返回错误。

import random

import operator

operation=[

    (operator.add, "+"),
    (operator.mul, "*"),
    (operator.sub, "-")
    ]
num_of_q=10
score=0

name=input("What is your name? ")
class_name=input("Which class are you in? ")
print(name,", welcome to this maths test!")


for _ in range(num_of_q):

    num1=random.randint(0,10)

    num2=random.randint(1,10)

    op,symbol=random.choice(operation)

    print("What is",num1,symbol,num2,"?")

    if input(int)==(num1,op,num2):

          print("Correct")
          score += 1
    else:
          print("Incorrect")

if num_of_q==10:

        print(name,"you got",score,"/",num_of_q)

Answer 1

此行不正确：

if input(int)==(num1,op,num2):

您必须将输入转换为int并将op应用于num1和num2：

if int(input()) == op(num1, num2):

Answer 2

你差不多了。出现错误的原因是您告诉input命令显示int作为提示，而不是将返回的值转换为int。

其次，您的计算答案的方法需要修复如下：

import random
import operator

operation=[
    (operator.add, "+"),
    (operator.mul, "*"),
    (operator.sub, "-")
    ]

num_of_q = 10
score = 0

name=input("What is your name? ")
class_name=input("Which class are you in? ")
print(name,", welcome to this maths test!")

for _ in range(num_of_q):
    num1=random.randint(0,10)
    num2=random.randint(1,10)
    op, symbol=random.choice(operation)
    print("What is",num1,symbol,num2,"?")

    if int(input()) == op(num1, num2):
          print("Correct")
          score += 1
    else:
          print("Incorrect")

print(name,"you got",score,"/",num_of_q)

如何让用户在Python 3中输入数字？

2 个答案: