Question

我是SQL的新手，我想知道是否可以在WHERE子句之后添加条件。更具体地说，我试图找出＆＃34;哪个项目已经卖给了两个人＆＃34;在我的数据库中。

我设法将所有已售出的商品连接到人们，并希望条件只提供已售出给两个人的商品。我尝试在COUNT(customer_id)子句中使用WHERE，但它在WHERE子句＆＃34;中提供了＃34;不允许的聚合。

修改

数据库表格为：

books((book_id), title, author_id, subject_id) 
publishers((publisher_id), name, address) 
authors((author_id), last_name, first_name) 
stock((isbn), cost, retail_price, stock) 
shipments((shipment_id), customer_id, isbn, ship_date) 
customers((customer_id), last_name, first_name) 
editions((isbn), book_id, edition, publisher_id, publication_date) 
subjects((subject_id), subject, location)

我当前的查询是：

SELECT title, first_name, last_name 
FROM books, shipments, customers, editions 
WHERE books.book_id = editions.book_id 
AND editions.isbn = shipments.isbn 
AND shipments.customer_id = customers.customer_id 
AND COUNT(customers.customer_id) = 2;

谢谢大家！

Answer 1

您需要使用HAVING子句，如下所示：

SELECT column_name, aggregate_function(column_name)
FROM table_name
WHERE column_name operator value
GROUP BY column_name
HAVING aggregate_function(column_name) operator val

UE;

Answer 2

您应该学习如何使用正确的join语法和表别名：

SELECT b.title, c.first_name, c.last_name 
FROM books b join
     editions e
     on b.book_id = e.book_id  join
     shipments s
     on e.isbn = s.isbn join
     customers c
     on s.customer_id = c.customer_id
GROUP BY title, first_name, last_name 
HAVING COUNT(customers.customer_id) = 2;

您的问题的答案是HAVING子句以及GROUP BY。

SQL查询 - 如何在WHERE子句

2 个答案: