Question

我正在为我的CS课程做一个程序。它并不难设置，它可以完成预期的工作。我的问题是，我希望它在同一行上获取所有输入而没有任何空格。该程序应该取ISBN的前9位数，找到第十位并打印出来。我知道你可以通过将数字作为字符串然后解析它来实现这一点（我相信？）所以你可以得到单独的整数。虽然我不完全确定我上次尝试正确设置while循环但这样做会让我不得不完全改变我的代码吗？这是问题所在：（商业：检查ISBN-10）ISBN-10（国际标准书号）由10位数字组成：d1d2d3d4d5d6d7d8d9d10。最后一位数字d10是校验和，使用以下公式从其他九位数计算：（d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5 + d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9）％11 如果校验和为10，则根据ISBN-10将最后一位数字表示为X. 惯例。编写一个程序，提示用户输入前9位数字显示10位ISBN（包括前导零）。你的程序应该阅读输入为整数。这里的任何一种方法都是没有循环的代码用白色空间输入输入：

/* Class:        CS1301
* Section:       9:30
* Term:          Fall 2015
* Name:          Matthew Woolridge
* Instructor:    Mr. Robert Thorsen
* Assignment:    4
* Program:       1
* ProgramName:   ISBN_Number
* Purpose:       Prompts the user to enter the first nine numbers of an ISBN and calculates the tenth
* Operation:     The information to be numbers are statically instantiated in the code and
*                the table is output to the screen.
* Input(s):      The user inputs the first nine ISBN numbers
* Output(s):     The output will be the full the tenth ISBN number in the full number
* Methodology:   The program will use if statements and defined variables which use the user input variables to calculate the ISBN
* and return it to the user.
*
*/

import java.util.Scanner;
public class ISBN_Number
{

   public static void main (String[] args)
   {

     /******************************************************************************
      *                          Declarations Section                               *
      ******************************************************************************/
      /****************************CONSTANTS********************************/
      int [] ISBN = new int [8];
      int num1 = 0;
      int nextNum;
      int i; 
      int input=0;
      int num10=0;
      String fullIsbn;

      Scanner scan = new Scanner (System.in); //Scanner utility initialization

     /******************************************************************************
      *                             Inputs Section                                  *
      ******************************************************************************/

      System.out.print("Please input the first nine digits (between 0-9) of your ISBN not including the leading 0: ");
      for (i = 0; i<ISBN.length;i++)
      {
         nextNum = scan.nextInt(); // For loop that asks for an input until it fills the array of 8
         ISBN[i] = nextNum;
         ++input;
      }

     /****************************variables********************************/
      if (input == 8)
      {
       num10 = (ISBN[0] * 1 + ISBN[1] * 2 + ISBN[2] * 3 + ISBN[3] * 4 + ISBN[4] * 5 + ISBN[5] * 6 + ISBN[6] * 7 + ISBN[7] * 8 + ISBN[8] * 9) % 11; // Calculates the value of num10
      }
      else 
      {
       System.out.println("You did not input enough or input too many digits.");
      }

     /******************************************************************************
      *                             Processing Section                            *
      ******************************************************************************/

      if (num10 == 10)
      { 
         fullIsbn = num1 + ISBN[0] + "" + ISBN[1] + "" + ISBN[2] + "" + ISBN[3] + "" + ISBN[4] + "" + ISBN[5] + "" + ISBN[6] + "" + ISBN[7] + "" + ISBN[8] + "" + "X";
      }
      else  // Determines if num10 is equal to x or not and prints
      {
         fullIsbn = num1 + "" + ISBN[0] + "" + ISBN[1] + "" + ISBN[2] + "" + ISBN[3] + "" + ISBN[4] + "" + ISBN[5] + "" + ISBN[6] + "" + ISBN[7] + "" + ISBN[8] + "" + num10;
      }

      /******************************************************************************
       *                              Outputs Section                                *
       ******************************************************************************/

      System.out.print("The full ISBN number is " + fullIsbn); // Prints the full 10 digit isbn
   } // Rnds string
} // Ends program

如何在没有空格的同一行上获取多个输入

0 个答案: