Question

我的目标是在表格中显示来自DOC_sql和MDT_sql的数据。找不到关于如何实施这种联系的解决方案。

目标是搜索文档并根据匹配的标签显示文档。

输入数据

CALL SearthDocuments('\'Book\',\'Currency\'', 'en_ENG');

代码

DELIMITER //
CREATE PROCEDURE SearthDocuments(IN VAR_TT_names VARCHAR(255), VAR_LANG_prefix CHAR(6))
BEGIN

SET @TT_sql = CONCAT('SELECT TAG_ID FROM TagTranslate WHERE TT_text IN (', VAR_TT_names, ')');
SET @DOC_ID_sql = CONCAT('SELECT DOC_ID FROM DocumentTag WHERE TAG_ID IN (', @TT_sql, ') GROUP BY DOC_ID HAVING COUNT(DOC_ID)');

SET @DOC_sql = CONCAT('SELECT * FROM VIEW_Document WHERE DOC_ID IN (', @DOC_ID_sql, ') AND LANG_prefix = "', VAR_LANG_prefix, '"' );
SET @MDT_sql = CONCAT('SELECT DOC_ID, count(*) as TAG_HITS FROM DocumentTag WHERE TAG_ID IN (', @TT_sql, ') GROUP BY DOC_ID HAVING COUNT(DOC_ID)');

-- SET @COM_sql = CONCAT('?')
-- PREPARE COM_stmt FROM @COM_sql;
-- EXECUTE COM_stmt;
-- DEALLOCATE PREPARE COM_stmt;
END
// DELIMITER ;

两个表都有标识符DOC_ID

表：DOC_sql

DOC_ID, DT_ID, DT_desc, DT_title, A_name, LANG_prefix

表：MDT_sql

DOC_ID, TAG_HITS

Answer 1

这是问题的解决方案。工作代码。

  ID DAY       TYPE_ID TYPE  NUM START_DATE END_DATE 
---- --------- ------- ---- ---- ---------  ---------
4241 15/09/15        2    1   66  01/01/00   31/12/99  
4241 16/09/15        2    1   66  01/01/00   31/12/99  
4241 17/09/15        9    1   59  17/09/15   18/09/15  
4241 18/09/15        9    1   59  17/09/15   18/09/15  
4241 19/09/15        2    1   66  01/01/00   31/12/99  
4241 20/09/15        2    1   66  01/01/00   31/12/99  

4241 15/09/15        3    2   63  01/01/00   31/12/99  
4241 16/09/15        8    2  159  16/09/15   17/09/15  
4241 17/09/15        8    2  159  16/09/15   17/09/15 
4241 18/09/15        3    2   63  01/01/00   31/12/99   
4241 19/09/15        3    2   63  01/01/00   31/12/99  
4241 20/09/15        3    2   63  01/01/00   31/12/99  

2134 15/09/15        2    1   66  01/01/00   31/12/99  
2134 16/09/15        2    1   66  01/01/00   31/12/99  
2134 17/09/15        9    1   59  17/09/15   18/09/15  
2134 18/09/15        9    1   59  17/09/15   18/09/15  
2134 19/09/15        2    1   66  01/01/00   31/12/99  
2134 20/09/15        2    1   66  01/01/00   31/12/99  

2134 15/09/15        3    2   63  01/01/00   31/12/99  
2134 16/09/15        8    2  159  16/09/15   17/09/15  
2134 17/09/15        8    2  159  16/09/15   17/09/15 
2134 18/09/15        3    2   63  01/01/00   31/12/99   
2134 19/09/15        3    2   63  01/01/00   31/12/99  
2134 20/09/15        3    2   63  01/01/00   31/12/99

Mysql在处理后连接两个concat表

1 个答案: