读取用户输入并存储到阵列时出错

时间:2015-09-19 11:03:33

标签: c arrays scanf

运行此代码时遇到错误。将有一个"程序停止工作"窗口一旦到达循环就扫描用户输入的名称(" scanf_s(%s",& nameptr [i]);)。 任何帮助或建议将不胜感激!

#include <stdio.h>
#include <string.h>
#define SIZE 10
int findTarget(char *target, char nameptr[SIZE][80], int size);

int main()
    {
    char nameptr[SIZE][80];
    char t[40];
    int i, result, size;
    printf("Enter no. of names: ");
    scanf_s("%d", &size);
    printf("Enter %d names: ", size);


    for (i = 0; i < size; i++) 
            scanf_s("%s", &nameptr[i]); 

    printf("Enter target name: ");
    scanf_s("\n");
    gets(t);
    result = findTarget(t, nameptr, size);
    printf("findTarget(): %d\n", result);

    return 0;

    }

    int findTarget(char *target, char nameptr[SIZE][80], int size)
      {
      int i;
      for (i = 0; i<size; i++) {
      if (strcmp(nameptr[i], target) == 0)
        return i;
        }
    return -1;
      }

1 个答案:

答案 0 :(得分:1)

此:

scanf_s("%s", &nameptr[i]); 

应该是

scanf_s("%s", nameptr[i], sizeof(nameptr[i])); 
/* Or better */
scanf_s("%79s", nameptr[i], sizeof(nameptr[i])); 

scanf_s("%s", nameptr[i], _countof(nameptr[i])); 
/* Or better */
scanf_s("%79s", nameptr[i], _countof(nameptr[i])); 

因为%s中的scanf_s需要第三个参数来表示所使用的字符串参数的最大大小。有关这方面的更多信息,请访问msdn documentation of scanf_s