Question

我想在SQL Server中找到这两个选择的总和：

select count(rez1)*3 as Fit1 from Table_Name where rez1>rez2 

select count(rez1)*1 as Fit2 from Table_Name where rez1=rez2

Answer 1

您可以将where子句转换为case表达式并返回整数值，而这些值又可以求和：

SELECT SUM (CASE WHEN rez1 > rez2 THEN 3
                 WHEN rez1 = rez2 THEN 1
            END)
FROM   table_name

Answer 2

一种可能的方式：

SELECT SUM(T.Fit) AS SumFit
FROM
    (
        select count(rez1)*3 as Fit
        from Table_Name where rez1>rez2

        UNION ALL

        select count(rez1)*1 as Fit
        from Table_Name where rez1=rez2
    ) AS T

如何一起找到两个选择的总和

2 个答案: