Question

我已经创建了一个Android应用程序，因为我使用此代码从服务器接收json对象，我需要从android发送来自同一个android活动的json对象我该怎么办？强文 < / p>

class GetDataJSON extends AsyncTask<String, Void, String> {
    private Dialog loadingDialog;

    @Override
    protected void onPreExecute() {
        super.onPreExecute();
        loadingDialog = ProgressDialog.show(anscheck.this, "Please wait",
                "Loading...");
    }

    @Override
    protected String doInBackground(String... params) {
        InputStream inputStream = null;

        String result = null;

        try {

            DefaultHttpClient httpclient = new DefaultHttpClient(
                    new BasicHttpParams());
            HttpPost httppost = new HttpPost(url);

            httppost.setHeader("Content-type", "application/json");

            HttpResponse response = httpclient.execute(httppost);
            HttpEntity entity = response.getEntity();

            inputStream = entity.getContent();
            // json is UTF-8 by default
            BufferedReader reader = new BufferedReader(new InputStreamReader(
                    inputStream, "UTF-8"), 8);
            StringBuilder sb = new StringBuilder();

            String line = null;
            while ((line = reader.readLine()) != null)

            {
                sb.append(line + "\n");

            }
            result = sb.toString();
        } catch (Exception e) {
            // Oops
        } finally {
            try {
                if (inputStream != null)
                    inputStream.close();
            } catch (Exception squish) {
            }
        }
        return result;
    }

    @Override
    protected void onPostExecute(String result) {

        loadingDialog.dismiss();
        String s = result.trim();

        {
            myJSON = result;
            showList();
        }
    }
}

Answer 1

您可以创建JSONObject您需要发布到服务器的任何数据，并将其设置为StringEntity到您的`HttpPost＆＃39;方法调用，下面我提供一些参考代码，

首先创建您需要发布的JSON数据，例如

public String loginArray() {
    JSONObject jsonObject = new JSONObject();
    try {
        jsonObject.put("email", uName);
        jsonObject.put("password", password);
    } catch (JSONException exception) {

    }

    UiUtils.showLog(jsonObject.toString());
    return jsonObject.toString();
}

现在将其设为StringEntity HttpPost即

httppost.setEntity(new StringEntity(loginArray())

在设置header

之前或之后写下此行

如何发送json对象并在单个代码中接收响应json对象Android

1 个答案: