Question

我的应用程序需要知道哪个iphone设备正在运行，并根据它进行一些屏幕调整。我使用以下代码来决定哪个iphone https://github.com/dennisweissmann/Basics/blob/master/Device.swift

但有没有办法找出是6S还是6S Plus？所以关键是如果不是Device.swift中提到的设备之一，那么不知道如何调整屏幕并显示不支持的设备，但我希望该应用程序的行为与iPhone6S的iPhone6相同，并且相同作为适用于iPhone6s Plus的iPhone6 Plus。

谢谢

Answer 1

您可以通过获取设备模型以编程方式执行此操作：

#import <sys/utsname.h>

NSString* deviceName()
{
    struct utsname systemInfo;
    uname(&systemInfo);

    return [NSString stringWithCString:systemInfo.machine encoding:NSUTF8StringEncoding];
}

结果模型：

@"i386"      on 32-bit Simulator
@"x86_64"    on 64-bit Simulator
@"iPod1,1"   on iPod Touch
@"iPod2,1"   on iPod Touch Second Generation
@"iPod3,1"   on iPod Touch Third Generation
@"iPod4,1"   on iPod Touch Fourth Generation
@"iPhone1,1" on iPhone
@"iPhone1,2" on iPhone 3G
@"iPhone2,1" on iPhone 3GS
@"iPad1,1"   on iPad
@"iPad2,1"   on iPad 2
@"iPad3,1"   on 3rd Generation iPad
@"iPhone3,1" on iPhone 4 (GSM)
@"iPhone3,3" on iPhone 4 (CDMA/Verizon/Sprint)
@"iPhone4,1" on iPhone 4S
@"iPhone5,1" on iPhone 5 (model A1428, AT&T/Canada)
@"iPhone5,2" on iPhone 5 (model A1429, everything else)
@"iPad3,4" on 4th Generation iPad
@"iPad2,5" on iPad Mini
@"iPhone5,3" on iPhone 5c (model A1456, A1532 | GSM)
@"iPhone5,4" on iPhone 5c (model A1507, A1516, A1526 (China), A1529 | Global)
@"iPhone6,1" on iPhone 5s (model A1433, A1533 | GSM)
@"iPhone6,2" on iPhone 5s (model A1457, A1518, A1528 (China), A1530 | Global)
@"iPad4,1" on 5th Generation iPad (iPad Air) - Wifi
@"iPad4,2" on 5th Generation iPad (iPad Air) - Cellular
@"iPad4,4" on 2nd Generation iPad Mini - Wifi
@"iPad4,5" on 2nd Generation iPad Mini - Cellular
@"iPhone7,1" on iPhone 6 Plus
@"iPhone7,2" on iPhone 6
@"iPhone8,1" on iPhone 6S
@"iPhone8,2" on iPhone 6S Plus

Answer 2

基于您的文件Device.swift，插入：

    case iPhone6S
    case iPhone6SPlus

下：

    case iPhone6Plus

并插入：

    case "iPhone8,1":                               self = iPhone6S
    case "iPhone8,2":                               self = iPhone6SPlus

下：

    case "iPhone7,1":                               self = iPhone6Plus

Answer 3

如果您使用AutoLayout，则无需检查您的应用正在运行哪款iPhone，系统会自动进行更改。

Answer 4

您可以使用此switch

public extension UIDevice {
var modelName: String {
    var systemInfo = utsname()
    uname(&systemInfo)
    let machineMirror = Mirror(reflecting: systemInfo.machine)
    let identifier = machineMirror.children.reduce("") { identifier, element in
        guard let value = element.value as? Int8, value != 0 else { return identifier }
        return identifier + String(UnicodeScalar(UInt8(value)))
    }

    switch identifier {
    case "iPhone3,1", "iPhone3,2", "iPhone3,3", "iPhone4,1":
        return "iPhone 4"

    case "iPhone5,1", "iPhone5,2", "iPhone5,3", "iPhone5,4", "iPhone6,1", "iPhone6,2", "iPhone8,4":
        return "iPhone 5"

    case "iPhone7,2", "iPhone8,1", "iPhone9,1", "iPhone9,3":
        return "iPhone 6,7"

    case "iPhone7,1", "iPhone8,2", "iPhone9,2", "iPhone9,4":
        return "iPhone Plus"

    case "i386", "x86_64":
        return "Simulator"
    default:
        return identifier
    }
}

}

然后是我的代码：

switch UIDevice.current.modelName {
    case "iPhone 4":
        //Your code here
    case "iPhone 5":
        //Your code here
    case "iPhone 6,7":
        //Your code here
    case "iPhone Plus", "Simulator":
        //Your code here
    default:
        break
    }

如何检测iPhone 6s和6s +

4 个答案: